我有一个包含这些字段的表
id sell_date
a1 27/7/2012
a1 26/7/2012
a1 24/7/2012
a1 24/2/2012
我想要计算当前日期前一年内销售的月份。结果
a1 = 2
假设 sell_date 是 DATE 类型:
SELECT COUNT(DISTINCT MONTH(sell_date)) FROM `mytable`
WHERE id='a1'
AND sell_date>=DATE_SUB(NOW(),INTERVAL 1 YEAR);
还,
删除id='a1' AND
将为您提供与任何 id 关联的销售额(在去年期间)的月数。像这样:
SELECT COUNT(DISTINCT MONTH(sell_date)) FROM `mytable`
WHERE sell_date>=DATE_SUB(NOW(),INTERVAL 1 YEAR);
还,
您可以获得每个 id 的列表以及去年与该 id 关联的销售额的月数,如下所示:
SELECT COUNT(DISTINCT id,MONTH(sell_date)) FROM `mytable`
WHERE sell_date>=DATE_SUB(NOW(),INTERVAL 1 YEAR);
您需要 datediff() 函数:
select count(id) as N
from table_name
where datediff(curdate(), sell_date) >= 365;
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_datediff http://dev.mysql.com/doc/refman/5.1/en/date-and -time-functions.html#function_curdate