grails - 将 groovy sql 的 sql.eachRow() 存储到 List

Question

你知道如何存储结果

    sql.eachRow()

groovy sql 的列表？例如 def personList = [] ？

例子：

    sql.eachRow('select lastname from users where id='active')

我想要的是存储结果，即。将姓氏添加到列表中，即 def personlist = []; 我知道我可以通过 namedQuery 轻松做到这一点，而且我已经做到了。但他们对此有一些潜在的原因。提前致谢。

Answer 1

def reqdColName = "lastname"
def query = "select $reqdColName from users where id='active'"

直接选项是使用rows () 方法。

def list= Sql.rows(query) //returns groovyrowresult as list

---

另一种选择是您可以改用executeQuery来获取查询的结果集，从而获得一个数组/列表。

def array = Sql.executeQuery(query).getArray(reqdColName)

//If you need as a list
def personList = Arrays.asList(array) 

Answer 2

I know that the question has been asked a long time ago, but still, I feel the answer may be of help for someone out there.

  def personlist = []
    sql = Sql.newInstance(url, username, password, driver)
    query = "select $reqdColName from users where id='active'"
    sql.eachRow(query)
    {
       row-> personlist << row.toString()
    }
    sql.close()

    personlist.each{println it}  // you can also return the list

Answer 3

def personList = sql.rows("select lastname from users where id='active'")*.lastname