0

有人可以指出我在这里做错了什么，这是我收到的错误消息；

 WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/logicalideasJPA/contacts.html] in DispatcherServlet with name 'appServlet'


<context:property-placeholder location="classpath:hibernate.properties" />

<!-- DispatcherServlet Context: defines this servlet's request-processing 
    infrastructure -->

<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />

<!-- Handles HTTP GET requests for /resources/** by efficiently serving 
    up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />

<!-- Resolves views selected for rendering by @Controllers to .jsp resources 
    in the /WEB-INF/views directory -->
<beans:bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <beans:property name="prefix" value="/WEB-INF/views/" />
    <beans:property name="suffix" value=".jsp" />
</beans:bean>

<context:component-scan base-package="com.logicalideasJPA.persistence" />
<context:component-scan base-package="com.logicalideasJPA.controller" />
<context:component-scan base-package="com.logicalideasJPA.dao" />

<!-- Enables the Spring MVC @Controller programming model -->
<tx:annotation-driven transaction-manager="transactionManager" />

<!-- Declare a JPA entityManagerFactory -->
<beans:bean id="entityManagerFactory"
    class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <beans:property name="dataSource" ref="dataSource" />
    <beans:property name="packagesToScan" value="com.logicalideasJPA.persistence" />
    <beans:property name="loadTimeWeaver">
        <beans:bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver" />
    </beans:property>
    <beans:property name="jpaVendorAdapter">
        <beans:bean
            class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
            <beans:property name="showSql" value="true" />
        </beans:bean>
    </beans:property>
</beans:bean>

<!-- Declare a transaction manager -->
<beans:bean id="transactionManager"
    class="org.springframework.orm.jpa.JpaTransactionManager">
    <beans:property name="entityManagerFactory" ref="entityManagerFactory" />
    <beans:property name="dataSource" ref="dataSource" />
</beans:bean>

<beans:bean id="dataSource"
    class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <beans:property name="driverClassName" value="${database.driver}" />
    <beans:property name="url" value="${database.url}" />
    <beans:property name="username" value="${database.user}" />
    <beans:property name="password" value="${database.password}" />
</beans:bean>


@Controller
public class ContactController {

@Autowired
private ContactsImp serviceInter;

@RequestMapping(method = RequestMethod.GET)
public String showContactForm(Map<String, Contacts> map){
    Contacts contacts = new Contacts();
    map.put("contacts", contacts);
    return "contacts";
}

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<!-- The definition of the Root Spring Container shared by all Servlets 
    and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Processes application requests -->
<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

非常感谢一些帮助。谢谢

4

2 回答 2

0

您似乎正在向“/logicalideasJPA/contacts.html”发送请求，但没有处理此请求的控制器。

@Controller
@RequestMapping("/contacts")
public class ContactController {

@Autowired
private ContactsImp serviceInter;

@RequestMapping(method = RequestMethod.GET)
public String showContactForm(Map<String, Contacts> map){
    Contacts contacts = new Contacts();
    map.put("contacts", contacts);
    return "contacts";
}

通过上述更改，您的请求应在 /contacts uri 处理

于 2012-07-24T22:01:54.090 回答
0

我认为这与您从控制器返回联系人的事实有关。默认视图解析器正在寻找合适的 HTML 文件来显示结果。您是要返回响应正文实体还是直接访问某种视图页面？

于 2012-07-24T21:30:11.807 回答