6

我正在尝试在 ListView 内单击的项目上方/下方显示一个弹出窗口。但是，问题是来自 OnItemClick 方法的 View 只给了我相对于 ListView 本身的 X 和 Y 值。我还检查了 ListView，这也给了我 x=0 y=0 尽管上面还有其他视图。

我浏览了hierarchyviewer 中的所有值，但没有看到我正在寻找的值。（并不是我在让它再次工作时遇到重大问题）。

有什么建议吗？

@Override
public void onListItemClick(ListView listView, View view, int position, long id) {
    LayoutInflater inflater = getLayoutInflater(null);
    PopupWindow quickRail = new PopupWindow(
            inflater.inflate(R.layout.quanitity_controls, null), view.getMeasuredWidth(),
            view.getMeasuredHeight());

    int[] location = {
            0, 0
    };

    // This doesn't place this window right on top of the view
    quickRail.showAtLocation(view, Gravity.CENTER, 0, location[1]);
}

列表中的两个项目都使弹出窗口出现在同一个地方。 弹出窗口未出现在所需位置

4

3 回答 3

9

这应该工作

//Activity windows height
int totalHeight = getWindowManager().getDefaultDisplay().getHeight();
int[] location = new int[2];
v.getLocationOnScreen(location);

位置数组应该具有视图的 x 和 y 值。'v' 是在 onItemClickListener 上传递的视图对象。

我添加了一些我用于我的项目的部分。这可能会有所帮助。我在列表视图的顶部有一个操作栏，这段代码似乎工作正常。

要求是在列表项的顶部或下方放置一个小菜单。So when an item is selected, I check if the selected list item is in the upper half of the screen, if so put the menu below the list item otherwise put it on top of the list item. 这是代码

ListItem 点击代码

listView.setOnItemClickListener(new OnItemClickListener() {
    public void onItemClick(AdapterView<?> parent, View view, int position
           , long id) {
        showQuickActionMenu(position,view);
    }   
});

private void showQuickActionMenu(int pos, View v){
    LayoutInflater inflater = 
            (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    //This is just a view with buttons that act as a menu.  
    View popupView = inflater.inflate(R.layout.ticket_list_menu, null);
    popupView.findViewById(R.id.menu_view).setTag(pos);
    popupView.findViewById(R.id.menu_change_status).setTag(pos);
    popupView.findViewById(R.id.menu_add_note).setTag(pos);
    popupView.findViewById(R.id.menu_add_attachment).setTag(pos);

    window = PopupHelper.newBasicPopupWindow(TicketList.this);
    window.setContentView(popupView);
    int totalHeight = getWindowManager().getDefaultDisplay().getHeight();
    int[] location = new int[2];
    v.getLocationOnScreen(location);

    if (location[1] < (totalHeight / 2.0)) {
        PopupHelper.showLikeQuickAction(window, popupView, v
                , getWindowManager(),0,0,PopupHelper.UPPER_HALF);
    } else {
        PopupHelper.showLikeQuickAction(window, popupView, v
                , getWindowManager(),0, 0,PopupHelper.LOWER_HALF);
    }   
}

这是我使用的 PopupHelper 类

public class PopupHelper {
    public static final int UPPER_HALF = 0;
    public static final int LOWER_HALF = 1;

    public static PopupWindow newBasicPopupWindow(Context context) {
        final PopupWindow window = new PopupWindow(context);

        // when a touch even happens outside of the window
        // make the window go away
        window.setTouchInterceptor(new OnTouchListener() {
            public boolean onTouch(View v, MotionEvent event) {
                if(event.getAction() == MotionEvent.ACTION_OUTSIDE) {
                    window.dismiss();
                    return true;
                }
                return false;
            }
        });

        window.setWidth(WindowManager.LayoutParams.WRAP_CONTENT);
        window.setHeight(WindowManager.LayoutParams.WRAP_CONTENT);
        window.setTouchable(true);
        window.setFocusable(true);
        window.setOutsideTouchable(true);

        window.setBackgroundDrawable(
                new ColorDrawable(android.R.color.darker_gray));        
        return window;
    }

    /**
     * Displays like a QuickAction from the anchor view.
     * 
     * @param xOffset
     *            offset in the X direction
     * @param yOffset
     *            offset in the Y direction
     */
     public static void showLikeQuickAction(PopupWindow window, View root, 
             View anchor, WindowManager windowManager, int xOffset
             ,int yOffset,int section) {

         //window.setAnimationStyle(R.style.Animations_GrowFromBottomRight);

         int[] location = new int[2];
         anchor.getLocationOnScreen(location);

         Rect anchorRect = new Rect(location[0], location[1], location[0] + 
                 anchor.getWidth(), location[1] + anchor.getHeight());

         root.measure(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);

         int rootWidth = root.getMeasuredWidth();
         int rootHeight = root.getMeasuredHeight();

         int screenWidth = windowManager.getDefaultDisplay().getWidth();
         int screenHeight = windowManager.getDefaultDisplay().getHeight();

         int xPos = ((screenWidth - rootWidth) / 2) + xOffset;
         int yPos = anchorRect.top - rootHeight + yOffset;

         xPos = (screenWidth - rootWidth);
         if(section == UPPER_HALF){
             yPos = anchorRect.top + anchor.getMeasuredHeight();    
         } else {
             yPos = anchorRect.top - rootHeight;
         }
         window.showAtLocation(anchor, Gravity.NO_GRAVITY, xPos, yPos);
    }

}
于 2012-07-24T14:53:15.120 回答
1

对于那些坚持这个问题的人，请尝试使用此代码片段

popWindow.showAsDropDown(v);//v is your listview or recyclerview item Element that clicked.

希望这有帮助。

于 2015-10-14T11:41:50.463 回答
0

试试这个，看看它是否有效..

private  void setListViewHeightBasedOnChildren(ListView listView) {
    ListAdapter listAdapter = listView.getAdapter();
    if (listAdapter == null) {
        // pre-condition
        return;
    }
    int totalHeight = 0;
    int desiredWidth = MeasureSpec.makeMeasureSpec(listView.getWidth(), MeasureSpec.AT_MOST);
    for (int i = 0; i < listAdapter.getCount(); i++) {
        View listItem = listAdapter.getView(i, null, listView);
        listItem.measure(desiredWidth, MeasureSpec.UNSPECIFIED);
        totalHeight += listItem.getMeasuredHeight();
    }

}

//这里listItem.getMeasuredHeight()会得到你每个列表项的高度...你可以通过height*clickedPosition得到你的位置

于 2012-07-24T14:31:17.857 回答