bash - 这个 bash 脚本给了我一个错误，我不知道为什么

Question

我在这里关注一些教程，每当我执行这个，我得到

Do you want to create a bukkit server on this computer? (Hint: answer YES or NO) > no
answered no
./test.sh: line 44: syntax error near unexpected token `else'
./test.sh: line 44: 'else'

这是脚本：

while true; do
    read -p "Do you want to create a bukkit server on this computer? (Hint: answer YES or NO) > " yn
    case $yn in
        [Yy]* ) echo answered yes; INSTALL="Y"; break;;
        [Nn]* ) echo answered no; break;;
        * ) echo "Please answer yes or no.";;
    esac
done

if [ -z "$INSTALL" ];
    echo "Yay!"
else
    echo "Sadface!"
fi

我是 bash 新手：/

Answer 1

您在then条件后缺少关键字：

if [ -z "$INSTALL" ]; then
    echo "Yay!"
else
    echo "Sadface!"
fi

Answer 2

你需要一个then之后if：

while true; do
read -p "Do you want to create a bukkit server on this computer? (Hint: answer YES or NO) > " yn
case $yn in
[Yy]* ) echo answered yes; INSTALL="Y"; break;;
[Nn]* ) echo answered no; break;;
* ) echo "Please answer yes or no.";;
esac
done

if [ -z "$INSTALL" ]; then
echo "Yay!"
else
echo "Sadface!"
fi