1

我还添加了 Chrome，但现在将其删除，因为它根本没有效果。在存储信息的 MySQL 中，它显示了适用于 Mozilla 和 Chrome 的 mozilla。为什么？Chrome 有自己的代码吗？

function getBrowserType () {
    if (!empty($_SERVER['HTTP_USER_AGENT']))
    {
       $HTTP_USER_AGENT = $_SERVER['HTTP_USER_AGENT'];
    }
    else if (!empty($HTTP_SERVER_VARS['HTTP_USER_AGENT']))
    {
       $HTTP_USER_AGENT = $HTTP_SERVER_VARS['HTTP_USER_AGENT'];
    }
    else if (!isset($HTTP_USER_AGENT))
    {
       $HTTP_USER_AGENT = '';
    }
    if (preg_match('/Opera(\/| )([0-9].[0-9]{1,2})/', $HTTP_USER_AGENT, $log_version))
    {
       $browser_version = $log_version[2];
       $browser_agent = 'opera';
    }
    else if (preg_match('/MSIE ([0-9].[0-9]{1,2})/', $HTTP_USER_AGENT, $log_version))
    {
       $browser_version = $log_version[1];
       $browser_agent = 'ie';
    }
    else if (preg_match('/OmniWeb\/([0-9].[0-9]{1,2})/', $HTTP_USER_AGENT, $log_version))
    {
       $browser_version = $log_version[1];
       $browser_agent = 'omniweb';
    }
    else if (preg_match('/Netscape([0-9]{1})/', $HTTP_USER_AGENT, $log_version))
    {
       $browser_version = $log_version[1];
       $browser_agent = 'netscape';
    }
    else if (preg_match('/Mozilla\/([0-9].[0-9]{1,2})/', $HTTP_USER_AGENT, $log_version))
    {
       $browser_version = $log_version[1];
       $browser_agent = 'mozilla';
    }
    else if (preg_match('/Konqueror\/([0-9].[0-9]{1,2})/', $HTTP_USER_AGENT, $log_version))
    {
       $browser_version = $log_version[1];
       $browser_agent = 'konqueror';
    }
    else
    {
       $browser_version = 0;
       $browser_agent = 'other';
    }
    return $browser_agent;
    }
4

2 回答 2

3

许多浏览器在其用户代理的开头都有 Mozilla/5.0 或其他东西。因此，如果您要检测这样的浏览器，可能会出现问题。但是，您可以使用此get_browser()功能为您执行此操作。它非常准确，您不必为这么多正则表达式而烦恼（您还需要不断更新）

http://php.net/manual/en/function.get-browser.php

它可以这样实现：

<?php
$browser = get_browser($_SERVER['HTTP_USER_AGENT'], true);
if($browser['browser'] == 'Mozilla'){
    echo 'Mozilla';
}else if($browser['browser'] == 'Chrome'){
    echo 'Chrome';
}
?>
于 2012-07-22T18:40:40.550 回答
2

http://php.net/manual/en/function.get-browser.php 我在这里找到的这段代码效果很好，经过测试。

<?php
function getBrowser() 
{ 
    $u_agent = $_SERVER['HTTP_USER_AGENT']; 
    $bname = 'Unknown';
    $platform = 'Unknown';
    $version= "";

    //First get the platform?
    if (preg_match('/linux/i', $u_agent)) {
        $platform = 'linux';
    }
    elseif (preg_match('/macintosh|mac os x/i', $u_agent)) {
        $platform = 'mac';
    }
    elseif (preg_match('/windows|win32/i', $u_agent)) {
        $platform = 'windows';
    }

    // Next get the name of the useragent yes seperately and for good reason
    if(preg_match('/MSIE/i',$u_agent) && !preg_match('/Opera/i',$u_agent)) 
    { 
        $bname = 'Internet Explorer'; 
        $ub = "MSIE"; 
    } 
    elseif(preg_match('/Firefox/i',$u_agent)) 
    { 
        $bname = 'Mozilla Firefox'; 
        $ub = "Firefox"; 
    } 
    elseif(preg_match('/Chrome/i',$u_agent)) 
    { 
        $bname = 'Google Chrome'; 
        $ub = "Chrome"; 
    } 
    elseif(preg_match('/Safari/i',$u_agent)) 
    { 
        $bname = 'Apple Safari'; 
        $ub = "Safari"; 
    } 
    elseif(preg_match('/Opera/i',$u_agent)) 
    { 
        $bname = 'Opera'; 
        $ub = "Opera"; 
    } 
    elseif(preg_match('/Netscape/i',$u_agent)) 
    { 
        $bname = 'Netscape'; 
        $ub = "Netscape"; 
    } 

    // finally get the correct version number
    $known = array('Version', $ub, 'other');
    $pattern = '#(?<browser>' . join('|', $known) .
    ')[/ ]+(?<version>[0-9.|a-zA-Z.]*)#';
    if (!preg_match_all($pattern, $u_agent, $matches)) {
        // we have no matching number just continue
    }

    // see how many we have
    $i = count($matches['browser']);
    if ($i != 1) {
        //we will have two since we are not using 'other' argument yet
        //see if version is before or after the name
        if (strripos($u_agent,"Version") < strripos($u_agent,$ub)){
            $version= $matches['version'][0];
        }
        else {
            $version= $matches['version'][1];
        }
    }
    else {
        $version= $matches['version'][0];
    }

    // check if we have a number
    if ($version==null || $version=="") {$version="?";}

    return array(
        'userAgent' => $u_agent,
        'name'      => $bname,
        'version'   => $version,
        'platform'  => $platform,
        'pattern'    => $pattern
    );
} 

// now try it
$ua=getBrowser();
$yourbrowser= "Your browser: " . $ua['name'] . " " . $ua['version'] . " on " .$ua['platform'] . " reports: <br >" . $ua['userAgent'];
print_r($yourbrowser);
?>
于 2012-07-23T10:04:01.240 回答