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下面是我的查询，在最后一行中，我试图查看日期之间的差异是否在 15 分钟内。但是每当我运行以下查询时。

SELECT TT.BUYER_ID , COUNT(*) FROM
(SELECT testingtable1.buyer_id, testingtable1.item_id, testingtable1.created_time from (select user_id, prod_and_ts.product_id as product_id, prod_and_ts.timestamps as timestamps from testingtable2 LATERAL VIEW explode(purchased_item) exploded_table as prod_and_ts where to_date(from_unixtime(cast(prod_and_ts.timestamps as BIGINT))) = '2012-07-09') prod_and_ts RIGHT OUTER JOIN (SELECT buyer_id, item_id, rank(buyer_id), created_time, UNIX_TIMESTAMP(created_time)
FROM (
    SELECT buyer_id, item_id, created_time
    FROM testingtable1
    where to_date(from_unixtime(cast(UNIX_TIMESTAMP(created_time) as int))) = '2012-07-09'
    DISTRIBUTE BY buyer_id
    SORT BY buyer_id, created_time desc
) a
WHERE rank(buyer_id) < 5) testingtable1 ON (testingtable1.item_id = prod_and_ts.product_id AND testingtable1.BUYER_ID = prod_and_ts.USER_ID 
AND abs(datediff(testingtable1.created_time,FROM_UNIXTIME(cast(prod_and_ts.timestamps as BIGINT)))) <= 15) where prod_and_ts.product_id IS NULL ORDER BY testingtable1.buyer_id, testingtable1.created_time desc) TT GROUP BY TT.BUYER_ID;

我总是得到例外 -

FAILED: Error in semantic analysis: line 10:144 Both Left and Right Aliases
Encountered in Join 15

我的查询有什么问题吗？或者在 Hive 中我们不能以分钟为单位计算日期之间的差异？任何建议将不胜感激。

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1 回答 1

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我认为问题在于您的加入。来自Hive 语言手册：

Hive 仅支持等式连接、外连接和左半连接。Hive 不支持非相等条件的连接条件，因为很难将此类条件表示为 map/reduce 作业。

于 2012-11-19T16:59:26.847 回答