4

这是一个例子:

require(ggplot2)
p <- ggplot(mtcars, aes(x = wt, y = mpg)) + geom_point()

yintercept <- c(5, 12, 20, 28, 29, 40)
col <- c("red", "blue", "green", "pink", "yellow", "tan")

# for the first level yintercept, and col 
p + geom_hline(aes(yintercept = 5), col = "red")

我有上面列出的更多级别的变量,而不是写长的“+”公式,我可以循环这个过程吗?对不起,简单的问题。

编辑:如何循环公式中的 x 或 y 变量

   myd <- data.frame (y = rnorm (100, 5, 10), X1 = rnorm (100, 5, 1), 
    X3 = rnorm (100, 10, 2), X4 = rnorm (100, 50,4))

x <- c("X1",  "X2",   "X3", "X4")

p <- ggplot(myd, aes(y = y)) + 
 mapply ( function (x) (geom_point(x = aes_string (x))))
4

2 回答 2

5

ggplot2执行此操作的方法是始终数据放入数据框中并映射美学。它使事情变得更简单:

df <- data.frame(yint = yintercept)

# for the first level yintercept, and col 
p + geom_hline(data = df,aes(yintercept=yint,colour = factor(yint))) + 
    scale_colour_manual(values = col,guide = "none")
于 2012-07-20T00:49:47.263 回答
4

尝试

p+mapply(function(a,b){dum<-aes_string(yintercept=a);
                       geom_hline(dum, col = b)},a=yintercept,b=col)
于 2012-07-20T00:46:49.847 回答