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我有 4 个带有标签号的按钮：0、1、2、3。我想在点击它时改变它的颜色。所以这就是我正在做的事情：

switch ([sender tag]) {
        case 0:
                   [myButton0 setBackgroundColor:[UIColor redColor]];
                   break;
        case 1:
           [myButton1 setBackgroundColor:[UIColor redColor]];
                    break;
        case 2:
           [myButton2 setBackgroundColor:[UIColor redColor]];
            break;
        case 3:
                   [myButton3 setBackgroundColor:[UIColor redColor]];
           break;
}

我的问题是，如果有什么方法可以缩短代码，比如我们通过它的标签号设置背景颜色？

谢谢

4

1 回答 1

1

这就是我正在做的事情。我在 UIColor 上为 colorWithHexValue 创建了一个类别。您可以使用您的代码。

 [signInButton setTitle:@"Sign In" forState:UIControlStateNormal];
signInButton.titleLabel.font = [UIFont boldSystemFontOfSize:15];
gradientLayer = [UIColor setGradientEffect:signInButton initialColor:0x797979 endColor:0x424242];
[[signInButton layer] insertSublayer:gradientLayer atIndex:0]; 
[signInButton setTitleColor:[UIColor colorWithHexValue:0xFFFFFF] forState:UIControlStateNormal];
[signInButton setTitleColor:[UIColor colorWithHexValue:0x000000] forState:UIControlStateSelected];

请用

enum {
UIControlStateNormal       = 0,                       
UIControlStateHighlighted  = 1 << 0,                  // used when UIControl isHighlighted is set
UIControlStateDisabled     = 1 << 1,
UIControlStateSelected     = 1 << 2,                  // flag usable by app (see below)
UIControlStateApplication  = 0x00FF0000,              // additional flags available for application use
UIControlStateReserved     = 0xFF000000               // flags reserved for internal framework use

};

于 2012-07-17T14:54:14.240 回答