mysql - $sql = mysql_query("SELECT * FROM books WHERE tags LIKE '%$_GET[term]%' LIMIT 0,$_GET[results]");

Question

我正在尝试制作一个 Like 搜索引擎，这对我的网站来说很简单。这是我正在使用的代码：

  $sql = mysql_query("SELECT * FROM books WHERE tags LIKE '%$_GET[term]%' LIMIT 0,$_GET
  [results]");

while($ser = mysql_fetch_array($sql)) {
    echo $ser['title']."<br />";


}

但是当它搜索时，它只会在我的标签中寻找一个词。有人对如何让它搜索我的所有标签有任何好主意吗？

Answer 1

i highly recommend not to use value directly from user first parse it, to protect yourself from SQL injections

try removing the limit and then check is it give same result?

Answer 2

Use this:-

$keywords =$_GET[term];
$keywords = explode('delimiter', $keyword);
$searchTermKeywords = array();
foreach ($keywords as $word) 
{

$searchTermKeywords[] = "tags LIKE '%$word%'";

}

$result= mysql_query("SELECT * FROM books WHERE ".implode(' AND ', $searchTermKeywords).");

Answer 3

$sql = mysql_query("SELECT * FROM books WHERE tags LIKE '%$_GET[term]%'");

从查询中删除限制，您应该从查询中获取所有匹配的行。