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我正在尝试将网页从常规 PHP 邮件切换到 PEAR 邮件。在此页面上，我希望将电子邮件发送给正在将其电子邮件输入 Web 表单的收件人。我正在尝试将 $to 设置为等于 $pickeremail，根据下面的代码，但是，唉，然后 PEAR 尝试将电子邮件发送到“$pickeremail”，而不是发送到用户在 Web 表单中实际输入的电子邮件.

$con = mysql_connect("localhost","BLAHBLAH","BLAHBLAH");

mysql_select_db("schoolh_SHS", $con);

if (!$con)
{
  die('Could not connect: ' . mysql_error());
}

$sql      = "UPDATE Donations SET `PICKER_NAME`='$_POST[pickername]',`PICKER_EMAIL`='$_POST[pickeremail]',`PICKER_PHONE`='$_POST[pickerphone]',`STATUS`='CLAIMED' WHERE DONATIONID = $_POST[id]";
$q        = "SELECT * FROM Donations WHERE DONATIONID = $_POST[id]";
$result   = mysql_query($q);
$Donation = mysql_fetch_array($result);

$orgname     = mysql_result($result,$i,"orgname");
$address     = mysql_result($result,$i,"address");
$city        = mysql_result($result,$i,"city");
$state       = mysql_result($result,$i,"state");
$pickeremail = mysql_result($result,$i,"picker_email");

if (!mysql_query($sql,$con))
{
  die('Error: ' . mysql_error());
}

function send_email($recipients, $from, $subject, $body)
{
  require_once "Mail.php";
  require_once "Mail/mime.php";

  $to         = '$pickeremail';
  $cc         = 'whynoceros@gmail.com';
  $recipients = $to.", ".$cc;
  $subject    = 'Pickup Confirmation';
  $from       = 'blah';
  $host       = 'blah';
  $username   = 'donations';
  $password   = 'blahblah';

  $headers = array (
    'From'    => $from,
    'To'      => $to,
    'Subject' => $subject
  );

  $mime = new Mail_mime();
  $mime->setHTMLBody($body);

  $body = $mime->get();
  $headers = $mime->headers($headers);

  $smtp = Mail::factory('smtp', array(
    'host'     => $host, 
    'auth'     => true,
    'username' => $username, 
    'password' => $password
  ));
  $mail = $smtp->send($recipients, $headers, $body);

  if (PEAR::isError($mail))
  {
    //return false;
    echo ($mail->getMessage());
  } 
  else 
  {
    return true; 
  }
}

根据下面的建议，我添加了一个 var_dump，结果是：

array(6) { ["MIME-Version"]=> string(3) "1.0" ["Content-Type"]=> string(29) "text/html; charset=ISO-8859-1" ["内容-Transfer-Encoding"]=> string(16) "quoted-printable" ["From"]=> string(33) "donations@schoolhousesupplies.org" ["To"]=> string(0) "" [" Subject"]=> string(19) "Pickup Confirmation" } 添加收件人失败：@localhost [SMTP：从服务器收到的响应代码无效（代码：501，响应：5.5.4 无效地址）]NULL

我注意到在标题数组中我有'To' => $to，我将其更改为'To' => $recipients。我还更改了行： $pickeremail = mysql_result($result,$i,"picker_email"); 收件人：$pickeremail=$_POST['pickeremail']; 现在，我得到了这个 var_dump: array(6) { ["MIME-Version"]=> string(3) "1.0" ["Content-Type"]=> string(29) "text/html; charset= ISO-8859-1" ["Content-Transfer-Encoding"]=> string(16) "quoted-printable" ["From"]=> string(33) "donations@schoolhousesupplies.org" ["To"]= > string(20) "whynoceros@gmail.com" ["Subject"]=> string(19) "Pickup Confirmation" } 添加收件人失败：@localhost [SMTP：从服务器收到的响应代码无效（代码：501，

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1 回答 1

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你在这里错了：

$to         = '$pickeremail';

因为在使用简单引号的时候，里面的 php 变量是不会被解释的。将此行替换为：

$to = $pickeremail;

编辑：

看转储：

["到"]=> 字符串(0) ""

您将一个空字符串放入$to. 因此，picker_email您的数据库中的字段似乎为空。你应该检查一下。

于 2012-07-14T17:49:07.557 回答