可能重复:
如何在 C++ 中拆分字符串?
C++ 拆分字符串
如何在 C++ 中从文件中拆分一行,如下所示?
我想保存具有以下格式的游戏输出结果:
CFC 1 - 0 RES
我有四个变量:
string team1;
string team2;
int goalst1;
int goalst2;
如何拆分字符串,使每个对应部分都在上述四个变量中?
可能重复:
如何在 C++ 中拆分字符串?
C++ 拆分字符串
如何在 C++ 中从文件中拆分一行,如下所示?
我想保存具有以下格式的游戏输出结果:
CFC 1 - 0 RES
我有四个变量:
string team1;
string team2;
int goalst1;
int goalst2;
如何拆分字符串,使每个对应部分都在上述四个变量中?
string team1;
string team2;
int goalst1;
int goalst2;
string dash;
std::cin >> team1 >> goalst1 >> dash >> goalst2 >> team2;
你可以做这样的事情,这需要#include <sstream>
:
char trash;
std::stringstream mystream(myInputString);
mystream >> team1 >> goalst1 >> trash>> goalst2 >> team2;
或者
char trash;
std::stringstream mystream;
mystream << myInputString;
mystream >> team1 >> goalst1 >> trash>> goalst2 >> team2;
编辑:这是更高级但有点整洁。将其粘贴在标题中:
#include <iostream>
#include <string>
#include <array>
#include <cstring>
template<class e, class t, int N>
std::basic_istream<e,t>& operator>>(std::basic_istream<e,t>& in, const e(&sliteral)[N]) {
std::array<e, N-1> buffer; //get buffer
in >> buffer[0]; //skips whitespace
if (N>2)
in.read(&buffer[1], N-2); //read the rest
if (strncmp(&buffer[0], sliteral, N-1)) //if it failed
in.setstate(in.rdstate() | std::ios::badbit); //set the state
return in;
}
template<class e, class t>
std::basic_istream<e,t>& operator>>(std::basic_istream<e,t>& in, const e& cliteral) {
e buffer; //get buffer
in >> buffer; //read data
if (buffer != cliteral) //if it failed
in.setstate(in.rdstate() | std::ios::badbit); //set the state
return in;
}
template<class e, class t, int N>
std::basic_istream<e,t>& operator>>(std::basic_istream<e,t>& in, e(&carray)[N]) {
return std::operator>>(in, carray);
}
template<class e, class t, class a>
std::basic_istream<e,t>& operator>>(std::basic_istream<e,t>& in, a& obj) {
return in >> obj; //read data
}
这允许您在流中执行字符串文字:
std::stringstream mystream(myInputString);
mystream >> team1 >> goalst1 >> '-' >> goalst2 >> team2;
或者
std::stringstream mystream;
mystream << myInputString;
mystream >> team1 >> goalst1 >> '-' >> goalst2 >> team2;
如果我做对了,您可能正在尝试从文件中读取。然后使用 ifstream,您可以像从 cin 这样的标准输入中读取文件一样读取文件。
IE
ifstream myfile("filename");
现在使用 myfile 而不是 cin 运算符,你就完成了..
我喜欢boost::split
这样的工作:
#include <string>
#include <vector>
#include <boost/algorithm/string/split.hpp>
struct Result {
std::string team1;
std::string team2;
unsigned goals1;
unsigned goals2;
};
Result split(std::string const& s) {
std::vector<std::string> splitted;
boost::split(s, splitted, boost::token_compress_on);
if (splitted.at(2) != "-") {
throw runtime_error("The string format does not match");
}
Result r;
r.team1 = splitted.at(0);
r.team2 = splitted.at(4);
r.goals1 = stoi(splitted.at(1));
r.goals2 = stoi(splitted.at(3));
return r;
}