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我从 AJAX 调用得到这个结果,我想将它传递给 jqgrid。格式与正常的 jqgrid 调用完全相同。我不知道为什么它不起作用,非常感谢任何帮助。

{"page":null,"total":2,"records":"16","rows":[{"id":"9910003","cell":["9910003","DEMO3","Test3 ","Sat,Sun","08:00:00","17:00:00","17","0"]},{"id":"9910004","cell":["9910004 ","DEMO4","Test4","Sat,Sun","08:00:00","17:00:00","19","0"]},{"id":"9910005" ,"cell":["9910005","DEMO5","Test5","Sat,Sun","08:00:00","17:00:00","17","0"]}, {"id":"9910006","cell":["9910006","DEMO6","Test6","Sat,Sun","08:00:00","17:00:00","17","0"]},{"id":"9910007","cell":["9910007","DEMO7","Test7","Sat,Sun", "08:00:00","17:00:00","14","0"]},{"id":"9910008","cell":["9910008","DEMO8","Test8 ","Sat,Sun","21:00:00","06:00:00","19","0"]},{"id":"9910009","cell":["9910009 ","DEMO9","Test9","Sat,Sun","21:00:00","06:00:00","14","0"]},{"id":"9910010" ,"单元格":["9910010","DEMO10","Test10","周六,周日","21:00:00","06:00:00","14","0"]},{"id":"9910011","cell":["9910011","DEMO11","Test11","Sat,Sun","21:00:00","06:00: 00","14","0"]},{"id":"9910012","cell":["9910012","DEMO12","Test12","Sat,Sun","21:00: 00","06:00:00","17","0"]},{"id":"9910013","cell":["9910013","DEMO13","Test13","Sat,太阳","21:00:00","06:00:00","16","0"]},{"id":"9910014","cell":["9910014","DEMO14" ,"Test14","Sat,Sun","21:00:00","06:00:00","14","0"]},{"id":"9910015","cell":["9910015","DEMO15","Test15","Sat,Sun","21:00:00","06:00:00","14","0"] },{"id":"9910016","cell":["9910016","DEMO16","Test16","Sat,Sun","21:00:00","06:00:00", "14","0"]}]}

以下是我的完整代码:

function report_grid() {
$.ajax({
    type: "POST",
    url: "filter_option.php?action=filter",
    data: $('#form1').serialize(),
    success: function(rdata) {

jQuery("#report-grid").jqGrid({
    data: rdata,
    datatype: "local",
    colNames:['Emp ID','firstName', 'surName', 'restDay','shift_In','shift_Out','late','undertime'],
    colModel:[
        {name:'emp_id',index:'emp_id', width:55},
        {name:'firstname',index:'firstname', width:90},
        {name:'surname',index:'surname', width:100},
        {name:'restday',index:'restday', width:80, align:"right"},
        {name:'shift_in',index:'shift_in', width:80, align:"right"},
        {name:'shift_out',index:'shift_out', width:80,align:"right"},
        {name:'late',index:'late', width:150, sortable:false},
        {name:'ut',index:'ut', width:150, sortable:false},
    ],
    height: 'auto',
    width: 'auto',
    rowNum:10,
    rowList:[10,15,20,30,50],
    pager: '#report-pager',
    sortname: 'emp_id',
    viewrecords: true,
    sortorder: "desc",
    caption:"Timesheet Summary"
});
jQuery("#report-grid").jqGrid('navGrid','#report-pager',{edit:false,add:false,del:false});

        }
    })
}

我在下面尝试但没有成功,我想我错过了一些东西

data:rdata.rows
datatype:"local" // shows only the id but with correct number of records

data:rdata.rows
datatype: "json" // shows nothing at all.
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1 回答 1

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现在明白了,我的json格式不正确,我应该参考演示页面中的数据数组。

于 2012-07-13T05:35:07.097 回答