7

我想通过使用数据类型的POST方法将在 iOS 上创建的新对象发送到接收服务器。JSON根据我对从iOS 中的服务器接收数据的了解，Apple 在引入 iOS 5 时简化了所有JSON处理。但与 GETting JSON 对象不同，在我能找到的任何地方都没有真正描述 POST ......

我尝试解决问题的第一步如下所示：

    //build an info object and convert to json
    NSDictionary *newDatasetInfo = [NSDictionary dictionaryWithObjectsAndKeys:name, @"name", language, @"language", nil];

    //convert object to data
    NSData* jsonData = [NSJSONSerialization dataWithJSONObject:newDatasetInfo options:kNilOptions error:&error];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:someURLSetBefore];
    [request setHTTPMethod:@"POST"];
    // any other things to set in request? or working this way?

    [[NSURLConnection alloc] initWithRequest:request delegate:self];
    // What to do with NSURLConnection? Or how to send differently?

但我真的不知道如何使用 POST 方法将 JSON 对象发送到服务器。有人可以帮我吗？

4

4 回答 4

16

I worked it out by trying a bit around, here's my code:

    //build an info object and convert to json
    NSDictionary *newDatasetInfo = [NSDictionary dictionaryWithObjectsAndKeys:name, @"name", language, @"language", nil];

    //convert object to data
    NSData* jsonData = [NSJSONSerialization dataWithJSONObject:newDatasetInfo options:kNilOptions error:&error];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:someURLSetBefore];
    [request setHTTPMethod:@"POST"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
    [request setHTTPBody:jsonData];

    // print json:
    NSLog(@"JSON summary: %@", [[NSString alloc] initWithData:jsonData
                                                     encoding:NSUTF8StringEncoding]);
    NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
    [connection start];
于 2012-07-11T16:37:56.897 回答
2 
- (IBAction)txtFetchData2:(id)sender {
NSString *queryString = [NSString stringWithFormat:@"http://example.com/username.php?name=%@", [self.txtName text]];
NSMutableURLRequest *theRequest=[NSMutableURLRequest
                          requestWithURL:[NSURL URLWithString:
                                          queryString]
                          cachePolicy:NSURLRequestUseProtocolCachePolicy
                          timeoutInterval:60.0];
NSDictionary* jsonDictionary = [NSDictionary dictionaryWithObjectsAndKeys:
                                @"Value1", @"Key1",
                                @"Value2", @"Key2",
                                nil];
NSError *error;
NSData* jsonData = [NSJSONSerialization dataWithJSONObject:jsonDictionary
                       options:NSJSONWritingPrettyPrinted error:&error];
[theRequest setHTTPMethod:@"POST"];
[theRequest addValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
// should check for and handle errors here but we aren't
[theRequest setHTTPBody:jsonData];
[NSURLConnection sendAsynchronousRequest:theRequest queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
    if (error) {
        //do something with error
    } else {
        NSString *responseText = [[NSString alloc] initWithData:data encoding: NSASCIIStringEncoding];
        NSLog(@"Response: %@", responseText);

        NSString *newLineStr = @"\n";
        responseText = [responseText stringByReplacingOccurrencesOfString:@"<br />" withString:newLineStr];            
        [self.lblData setText:responseText];
    }
}];
}
于 2015-12-08T07:47:13.470 回答
1

NSString *strUrl = @"URL"; NSURL *url = [NSURL URLWithString:strUrl];

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringLocalCacheData timeoutInterval:60.0];

// For set postdata in string
NSString *strPatientID = [NSString stringWithFormat:@"%@%@%@%@",self.txtDegit1.text,self.txtDegit2.text,self.txtDegit3.text,self.txtDegit4.text];
NSString *deviceToken = @"";
postString = [NSString stringWithFormat:@"practiceid=%@&email=%@&password=%@&devicetoken=%@",strPatientID,self.txtUsername.text,self.txtPassword.text,deviceToken];


NSMutableData *httpDataBody = [NSMutableData data];
[httpDataBody appendData:[postString dataUsingEncoding:NSUTF8StringEncoding]];

NSString *strPostLength = [NSString stringWithFormat:@"%lu",[httpDataBody length]];

if ([httpDataBody length ] > 0){

    [request addValue:@"application/x-www-form-urlencoded charset=utf-8" forHTTPHeaderField:@"Content-Type"];
    [request setHTTPMethod:@"POST"];
    [request addValue:strPostLength forHTTPHeaderField:@"Content-Type"];
    [request setHTTPBody:httpDataBody];

}

urlConnection = [[NSURLConnection alloc]initWithRequest:request delegate:self];
[urlConnection start];
于 2015-02-22T09:19:21.363 回答
0 
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:[NSURL URLWithString:[NSString stringWithFormat:@"http://webstar52.com/demo/webcommunity/work.php"]]];
    NSString *post = [NSString stringWithFormat:@"&tag=%@&user_id=%@",@"getcontact",@"10408"]; 
    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
    [request setHTTPMethod:@"POST"];      
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];
    [request setHTTPBody:postData];
  conn  = [[NSURLConnection alloc]initWithRequest:request delegate:self];
于 2013-12-30T14:52:53.160 回答