1

我知道这是一个愚蠢的问题，但我不知道该怎么做。从此链接 请求的链接可以返回带有 NSURLconnection 的 json 数据吗？我希望有人检查此链接并告诉我这是否可能，因为我是这方面的新手。

编辑：

我尝试使用NSJSONSerialization

- (void)viewDidLoad
{
    NSURLRequest *req = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.goalzz.com/main.aspx?region=-1&area=6&update=true"]];
    connectionData = [[NSURLConnection alloc]initWithRequest:req delegate:self];
    [super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
 }
- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {
    Data = [[NSMutableData alloc] init];
}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
    [Data appendData:data];
}

 - (void)connectionDidFinishLoading:(NSURLConnection *)connection {
NSError *jsonParsingError = nil;
id object = [NSJSONSerialization JSONObjectWithData:Data options:0 error:&jsonParsingError];

if (jsonParsingError) {
    NSLog(@"JSON ERROR: %@", [jsonParsingError localizedDescription]);
} else {
    NSLog(@"OBJECT: %@", [object class]);
}
}

我在控制台中收到此错误消息：

JSON 错误：操作无法完成。（可可错误 3840。）

4

1 回答 1

10

正如上面的评论所暗示的，该链接不返回 JSON。但是，假设您确实有这样的链接，您可以使用 NSJSONSerialization 类将 JSON 数据解析为 Objective-C 类：

http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSJSONSerialization_Class/Reference/Reference.html#//apple_ref/doc/uid/TP40010946

将此与 NSURLConnection 结合起来，您就可以按照您的要求进行操作。下面是实现 NSURLConnection 的演练：

http://developer.apple.com/library/ios/#documentation/Cocoa/Conceptual/URLLoadingSystem/Tasks/UsingNSURLConnection.html#//apple_ref/doc/uid/20001836-BAJEAIEE

这是您需要的概述。显然这不是工作代码：

- (void)downloadJSONFromURL {
    NSURLRequest *request = ....
    NSURLConnection *urlConnection = [[NSURLConnection alloc] initWithRequest:urlRequest delegate:self];
    // ...
}

NSMutableData *urlData;

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {
    urlData = [[NSMutableData alloc] init];
}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
    [urlData appendData:data];
}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
    NSError *jsonParsingError = nil;
    id object = [NSJSONSerialization JSONObjectWithData:urlData options:0 error:&jsonParsingError];

    if (jsonParsingError) {
        DLog(@"JSON ERROR: %@", [jsonParsingError localizedDescription]);
    } else {
        DLog(@"OBJECT: %@", [object class]);
    }
}
于 2012-07-03T21:58:28.030 回答