我开发了一个应用程序,它读取 java 项目内的 java 包中有多少文件,并计算这些单独文件中的代码行,例如在 java 项目中,如果有 2 个包有 4 个单独的文件,则读取的文件总数将是 4,如果这 4 个文件在每个文件中有 10 行代码,那么 4*10 在整个项目中总共有 40 行代码......下面是我的一段代码
private static int totalLineCount = 0;
private static int totalFileScannedCount = 0;
public static void main(final String[] args) throws FileNotFoundException {
JFileChooser chooser = new JFileChooser();
chooser.setCurrentDirectory(new java.io.File("C:" + File.separator));
chooser.setDialogTitle("FILES ALONG WITH LINE NUMBERS");
chooser.setFileSelectionMode(JFileChooser.DIRECTORIES_ONLY);
chooser.setAcceptAllFileFilterUsed(false);
if (chooser.showOpenDialog(null) == JFileChooser.APPROVE_OPTION) {
Map<File, Integer> result = new HashMap<File, Integer>();
File directory = new File(chooser.getSelectedFile().getAbsolutePath());
List<File> files = getFileListing(directory);
// print out all file names, in the the order of File.compareTo()
for (File file : files) {
// System.out.println("Directory: " + file);
getFileLineCount(result, file);
//totalFileScannedCount += result.size(); //saral
}
System.out.println("*****************************************");
System.out.println("FILE NAME FOLLOWED BY LOC");
System.out.println("*****************************************");
for (Map.Entry<File, Integer> entry : result.entrySet()) {
System.out.println(entry.getKey().getAbsolutePath() + " ==> " + entry.getValue());
}
System.out.println("*****************************************");
System.out.println("SUM OF FILES SCANNED ==>" + "\t" + totalFileScannedCount);
System.out.println("SUM OF ALL THE LINES ==>" + "\t" + totalLineCount);
}
}
public static void getFileLineCount(final Map<File, Integer> result, final File directory)
throws FileNotFoundException {
File[] files = directory.listFiles(new FilenameFilter() {
public boolean accept(final File directory, final String name) {
if (name.endsWith(".java")) {
return true;
} else {
return false;
}
}
});
for (File file : files) {
if (file.isFile()) {
Scanner scanner = new Scanner(new FileReader(file));
int lineCount = 0;
totalFileScannedCount ++; //saral
try {
for (lineCount = 0; scanner.nextLine() != null; ) {
while (scanner.hasNextLine()) {
String line = scanner.nextLine().trim();
if (!line.isEmpty()) {
lineCount++;
}
}
} catch (NoSuchElementException e) {
result.put(file, lineCount);
totalLineCount += lineCount;
}
}
}
}
/**
* Recursively walk a directory tree and return a List of all Files found;
* the List is sorted using File.compareTo().
*
* @param aStartingDir
* is a valid directory, which can be read.
*/
static public List<File> getFileListing(final File aStartingDir) throws FileNotFoundException {
validateDirectory(aStartingDir);
List<File> result = getFileListingNoSort(aStartingDir);
Collections.sort(result);
return result;
}
// PRIVATE //
static private List<File> getFileListingNoSort(final File aStartingDir) throws FileNotFoundException {
List<File> result = new ArrayList<File>();
File[] filesAndDirs = aStartingDir.listFiles();
List<File> filesDirs = Arrays.asList(filesAndDirs);
for (File file : filesDirs) {
if (file.isDirectory()) {
result.add(file);
}
if (!file.isFile()) {
// must be a directory
// recursive call!
List<File> deeperList = getFileListingNoSort(file);
result.addAll(deeperList);
}
}
return result;
}
/**
* Directory is valid if it exists, does not represent a file, and can be
* read.
*/
static private void validateDirectory(final File aDirectory) throws FileNotFoundException {
if (aDirectory == null) {
throw new IllegalArgumentException("Directory should not be null.");
}
if (!aDirectory.exists()) {
throw new FileNotFoundException("Directory does not exist: " + aDirectory);
}
if (!aDirectory.isDirectory()) {
throw new IllegalArgumentException("Is not a directory: " + aDirectory);
}
if (!aDirectory.canRead()) {
throw new IllegalArgumentException("Directory cannot be read: " + aDirectory);
}
}
但问题是它在计算单个文件的代码行时也会计算空白行,它不应该,请告知我需要在我的程序中做哪些修改,以便它在计算时不计算空白行单个文件的代码行。
我想到的想法只是将读取的字符串与“”进行比较,如果不等于“”(空)则计数 if(!readString.trim().equals("")) lineCount++ 请为此提供建议