5

我正在实现允许用户互相关注的功能。我有数据库表:

User{UserId, FirstName, LastName etc.}
Followings{FollowerUserId, FollowingUserId, CreatedOnDate etc.}

所以我添加了 EF 类:

public class Follow
    {
        [Key, Column(Order = 1)]
        public Guid FollowerUserId { get; set; }
        [Key, Column(Order = 2)]
        public Guid FollowUserId { get; set; }        
        public DateTime CreatedOnDate { get; set; }

        public virtual User Follower { get; set; }
        public virtual User Following { get; set; }
    }

最后两个虚拟属性会导致问题。当我打电话时:

var model = con.Follows.Where(x => x.FollowerUserId == uid);

我得到以下异常:

Invalid column name 'Following_UserId'.

该问题可能是由于一个类中有两个 User 对象引起的。知道如何解决这个问题吗?
更新

public class User
    {

        public Guid UserId { get; set; }
        ...
        public virtual ICollection<Follow> Following { get; set; }
        public virtual ICollection<Follow> Followers { get; set; }
    }
4

1 回答 1

4

我认为原因是外键属性 ( FollowerUserIdand FollowUserId) 和导航属性 ( Followerand Following) 不遵守命名约定,因此 EF 无法将第一个属性识别为外键。您可以通过使用属性显式指定 FK 属性来解决此问题[ForeignKey]

public class Follow
{
    [Key, Column(Order = 1), ForeignKey("Follower")]
    public Guid FollowerUserId { get; set; }
    [Key, Column(Order = 2), ForeignKey("Following")]
    public Guid FollowUserId { get; set; }        

    public DateTime CreatedOnDate { get; set; }

    public virtual User Follower { get; set; }
    public virtual User Following { get; set; }
}

编辑

至少第二个属性不遵守命名约定,第一个看起来不错。因此,或者您可以通过将第二个 FK 属性重命名FollowUserId为:

public Guid FollowingUserId { get; set; }        

...因为导航属性被调用Following

编辑 2

关于您的更新:您需要添加[InverseProperty]属性来告诉 EF 哪些导航属性属于一起:

public class Follow
{
    [Key, Column(Order = 1), ForeignKey("Follower")]
    public Guid FollowerUserId { get; set; }
    [Key, Column(Order = 2), ForeignKey("Following")]
    public Guid FollowUserId { get; set; }        

    public DateTime CreatedOnDate { get; set; }

    [InverseProperty("Followers")]  // refers to Followers in class User
    public virtual User Follower { get; set; }
    [InverseProperty("Following")]  // refers to Following in class User
    public virtual User Following { get; set; }
}
于 2012-06-30T11:07:19.320 回答