我正在编译以下代码并收到以下错误。如何解决这个问题?谢谢你的帮助。
错误 C2079:'issline' 使用未定义的类 'std::basic_istringstream<_Elem,_Traits,_Alloc>' 1> 和 1>
[ 1> _Elem=char, 1>
_Traits=std::char_traits, 1> _Alloc=std::分配器 1> ] 1>d:\technical\c++study\readparsing\readparsing\main.cpp(49) : 错误 C2440: 'initializing' : 无法从 'std::string' 转换为 'int' 1> 否可以执行此转换的用户定义的转换运算符可用,或者无法调用该运算符 1>d:\technical\c++study\readparsing\readparsing\main.cpp(51) : error C2678: binary '>>' : 未找到采用“int”类型的左操作数的运算符(或没有可接受的转换) 1>
d:\technical\c++study\readparsing\readparsing\timestamp.h(31): could be 'std::istream &operator >>(std::istream &,TimeStamp &)' 1>
同时尝试匹配参数列表'(int,时间戳)'
我在 TimeStamp.h 中有以下代码
#ifndef __TIMESTAMP_
#define __TIMESTAMP_
#include <iostream>
struct DateTime
{
unsigned int dwLowDateTime;
unsigned int dwHighDateTime;
};
class TimeStamp
{
public:
TimeStamp()
{
m_time.dwHighDateTime = 0;
m_time.dwLowDateTime = 0;
}
TimeStamp& operator = (unsigned __int64 other)
{
*( unsigned __int64*)&m_time = other;
return *this;
}
private:
DateTime m_time;
};
std::istream& operator >> (std::istream& input, TimeStamp& timeStamp);
#endif
在 main.cpp 我有以下
#include <iostream>
#include <algorithm>
#include <string>
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include "TimeStamp.h"
std::istream& operator >> (std::istream& input, TimeStamp& timeStamp)
{
// 1.
// use regular stream operator parsing technique to parse individual integer x values (separated in the form "xxxx-xx-xx xx:xx:xx.xxx")
// for year, month, day, hour, minute, seconds, mseconds
unsigned int year;
unsigned int month;
unsigned int day;
unsigned int hour;
unsigned int minute;
unsigned int seconds;
unsigned int milliSeconds;
char dash;
char colon;
input >> year >> dash >> month >> dash >> day >> hour >> colon >> minute >> colon >> seconds >> colon >> milliSeconds;
cout << "Time stamp opeator is called " << std::endl;
// 2.
// code to be written.
return input;
}
int main () {
std::string dateTime = "2012-06-25 12:00:10.000";
TimeStamp myTimeStamp;
std::istringstream issline(dateTime);
issline >> myTimeStamp;
return 0;
}