我正在尝试获取一个使用 XSLT 2.0 输出多个工作文件的示例。
将 Saxon B 9.7.0.1 与 Java 1.6 一起使用,我收到此错误:
C:\Documents and Settings\Administrator\Desktop\saxon>java -jar saxon9.jar -s:input.xml -xsl:transform.xml transform.xml 第 15 行的错误: java.net.URISyntaxException:索引 20 处的路径中存在非法字符:file:///C:/Documents 和 Settings/Administrator/Desktop/saxon/output1/test1.html 在 xsl:for-each (file:/C:/Documents%20and%20Settings/Administrator/Desktop/saxon/transform.xml#10) 处理 /tests/testrun[1] 转换失败:报告了运行时错误
输入.xml
<?xml version="1.0" encoding="UTF-8"?>
<tests>
<testrun run="test1">
<test name="foo" pass="true" />
<test name="bar" pass="true" />
<test name="baz" pass="true" />
</testrun>
<testrun run="test2">
<test name="foo" pass="true" />
<test name="bar" pass="false" />
<test name="baz" pass="false" />
</testrun>
<testrun run="test3">
<test name="foo" pass="false" />
<test name="bar" pass="true" />
<test name="baz" pass="false" />
</testrun>
</tests>
转换.xml
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output method="text"/>
<xsl:output method="html" indent="yes" name="html"/>
<xsl:template match="/">
<xsl:for-each select="//testrun">
<xsl:variable name="filename"
select="concat('output1/',@run,'.html')" />
<xsl:value-of select="$filename" /> <!-- Creating -->
<xsl:result-document href="{$filename}" format="html">
<html><body>
<xsl:value-of select="@run"/>
</body></html>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>