1

得到带有 Id、parentId、描述的数据表。它是一种关系表结构。

我希望能够将参数传递给一个函数，该函数是树视图中项目的当前选定 ID。我想返回一个包含所有相关子行的数据表，关系的顶部是 parentId 为空......等等

我想做这个 LINQ

欢迎任何帮助。

enter code here var kids = ( from p in dt.AsEnumerable()
                     where p.Field<Int32?>( "ParentId" ) == parentId
                     select new
                     {
                         parent = p,
                         child = from c in dt.AsEnumerable()
                                 where c.Field<Int32?>( "ParentId" ) == p.Field<Int32>( "Id" )
                                 select new
                                 {
                                     child = c
                                 }
                     } ).ToList();

以下是我正在使用的数据，我无法让它按预期工作。也许我们不是在谈论相同的最终结果，或者我错过了一些可怕的东西。

这是我拥有的代码，当我为 parentId 传递 57 的值时，我在子项中得到 2 行。

QuotationItemId=58 和 71

我也希望得到 QuotationItemId 59, 60, 55 ,56, 61 

        var lookup = dt.AsEnumerable().ToLookup( p => p.Field<int?>( "ParentId" ) );
        var children = lookup[parentId].ToList();

数据转储

4

2 回答 2

5

这是你可以做的：

var lookup =
    dt
        .AsEnumerable()
        .ToLookup(p => p.Field<int?>("ParentId"));

现在，如果您想要根元素，请执行以下操作：

var roots = lookup[null];

如果你想要任何孩子，给定parentId，你这样做：

var children = lookup[parentId];

很简单吧？

这是基于您的编辑的一些代码。

我使用匿名类型定义了我的项目列表：

var items = new []
{
    new { QuotationItemId = 54, ParentId = (int?)null, Description = "0000", },
    new { QuotationItemId = 55, ParentId = (int?)60, Description = "Product 55", },
    new { QuotationItemId = 56, ParentId = (int?)60, Description = "Product 56", },
    new { QuotationItemId = 57, ParentId = (int?)54, Description = "Category 57", },
    new { QuotationItemId = 58, ParentId = (int?)57, Description = "Sub Category 58", },
    new { QuotationItemId = 59, ParentId = (int?)58, Description = "Product 59", },
    new { QuotationItemId = 60, ParentId = (int?)58, Description = "Standard Ratel", },
    new { QuotationItemId = 61, ParentId = (int?)60, Description = "Product 61", },
    new { QuotationItemId = 62, ParentId = (int?)null, Description = "Stage 62", },
    new { QuotationItemId = 63, ParentId = (int?)62, Description = "Product 63", },
    new { QuotationItemId = 64, ParentId = (int?)62, Description = "Product 64", },
    new { QuotationItemId = 65, ParentId = (int?)62, Description = "Category 65", },
    new { QuotationItemId = 66, ParentId = (int?)65, Description = "Sub Category66", },
    new { QuotationItemId = 67, ParentId = (int?)66, Description = "Product 67", },
    new { QuotationItemId = 68, ParentId = (int?)66, Description = "Standard Rate 2", },
    new { QuotationItemId = 69, ParentId = (int?)68, Description = "Product 69", },
    new { QuotationItemId = 71, ParentId = (int?)57, Description = "Sub Category 71", },
    new { QuotationItemId = 72, ParentId = (int?)54, Description = "Category 72", },
    new { QuotationItemId = 73, ParentId = (int?)72, Description = "Sub Category73", },
    new { QuotationItemId = 74, ParentId = (int?)73, Description = "Product 74", },
    new { QuotationItemId = 75, ParentId = (int?)73, Description = "Product 75", },
    new { QuotationItemId = 77, ParentId = (int?)null, Description = "qqqqqqqqqq", },
    new { QuotationItemId = 78, ParentId = (int?)null, Description = "zzzzzz", },
    new { QuotationItemId = 79, ParentId = (int?)null, Description = "Test 12345", },
    new { QuotationItemId = 80, ParentId = (int?)null, Description = "456", },
    new { QuotationItemId = 81, ParentId = (int?)null, Description = "tttt", },
    new { QuotationItemId = 82, ParentId = (int?)null, Description = "reddddy777", },
    new { QuotationItemId = 83, ParentId = (int?)null, Description = "bbbbbbbbbbbb", },
    new { QuotationItemId = 84, ParentId = (int?)null, Description = "nnnnnnnnnnnnn", },
};

而且，使用 LINQPad，查找工作如下：

var lookup = items.ToLookup(x => x.ParentId);

lookup[58].Dump();
lookup[60].Dump();

来自 LINQPad 的屏幕转储

您应该注意，它不会一直递归下去。

如果你想一直递归，那么你需要定义一个递归函数。尝试这个：

Func<IEnumerable<Quotation>, IEnumerable<Quotation>> recurse = null;
recurse = qs =>
{
    return
        qs
            .Concat(
                from q in qs
                from q2 in recurse(lookup[q.QuotationItemId])
                select q2);
};

recurse(lookup[57]).Dump();

这给了你：

LINQPad 图像转储

这是我认为你所期待的。

于 2012-06-24T11:53:14.797 回答
-1

您可以简单地选择它们：

var kids = from p in db.Items
           where p.parentId == parentId
           select p

然后您将拥有：kids.Items作为列表。所以你可以通过一个简单的foreach循环来检索孩子，如下所示：

foreach(Item item in kids.Items)

希望能帮助到你。

于 2012-06-24T11:43:58.223 回答