3

如何在xcode 4.3 lion中找到将调用函数而不是搜索工具的地方?谢谢!

对不起,我的英语不好:我的意思是,假设我有一个名为 A 的类,而 A 类有一个函数 -(void)findMe; 我想要的是在我的项目中找到调用函数“-(void)findMe”的地方。

谢谢。

4

1 回答 1

0

I'm afraid the search feature is probably your best bet. This doesn't exactly solve your problem but you can "command - click" your function, and Xcode will jump to its declaration.

To speed up the search process, you can use "command - shift - F" to call up a project wide search, and "command - F" to search the current file.

于 2012-06-22T08:38:00.883 回答