iphone - 如何在xcode 4.3 lion中找到将调用函数而不是搜索工具的地方

Question

如何在xcode 4.3 lion中找到将调用函数而不是搜索工具的地方？谢谢！

对不起，我的英语不好：我的意思是，假设我有一个名为 A 的类，而 A 类有一个函数 -(void)findMe; 我想要的是在我的项目中找到调用函数“-(void)findMe”的地方。

谢谢。

Answer 1

I'm afraid the search feature is probably your best bet. This doesn't exactly solve your problem but you can "command - click" your function, and Xcode will jump to its declaration.

To speed up the search process, you can use "command - shift - F" to call up a project wide search, and "command - F" to search the current file.