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i am listing files from directories on click on that specific folder name, when files show in datagridview. Now using context menu i want to add this sendto option in that context menu and want to send that file to any removable media.

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2 回答 2

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您在 Windows 的“发送到”菜单中看到的程序快捷方式存储在%APPDATA%\Microsoft\Windows\SendTo文件夹中。

阅读此文件夹的内容并在网格的上下文菜单中显示选项。

快捷方式是.LNK文件。从 LNK 文件中解析 EXE 的名称并使用System.Diagnostics.Process.Run

这是从 LNK 文件中解析 EXE 位置的方法

http://social.msdn.microsoft.com/Forums/en-US/csharpgeneral/thread/8d0f33a3-af4d-498f-a37b-e6fc84136c4a/

于 2012-06-22T05:08:25.150 回答
0

尝试修改此示例，它在不同的列上启用不同的选项：

//Define different context menus for different columns
private ContextMenu contextMenuForColumn1 = new ContextMenu();
private ContextMenu contextMenuForColumn2 = new ContextMenu();

Add the following line of code in the form load event:

private void Form_Load(object sender, EventArgs e)
{
    // Load all default values of controls 
    populateDataGridView();

    // Add context mneu items
    contextMenuForColumn1.MenuItems.Add("Make Active", new     EventHandler(MakeActive));
    contextMenuForColumn2.MenuItems.Add("Delete", new     EventHandler(Delete));
    contextMenuForColumn2.MenuItems.Add("Register", new     EventHandler(Register));
}

Add the following code to mouseup event of the gridview:

private void dataGridView_MouseUp(object sender, MouseEventArgs e)
{
    // Load context menu on right mouse click
    DataGridView.HitTestInfo hitTestInfo;
    if (e.Button == MouseButtons.Right)
    {
        hitTestInfo = dataGridView.HitTest(e.X, e.Y);
        // If column is first column
        if (hitTestInfo.Type == DataGridViewHitTestType.Cell && hitTestInfo.ColumnIndex == 0)
            contextMenuForColumn1.Show(dataGridView, new Point(e.X, e.Y));
        // If column is second column
        if (hitTestInfo.Type == DataGridViewHitTestType.Cell && hitTestInfo.ColumnIndex == 1)
            contextMenuForColumn2.Show(dataGridView, new Point(e.X, e.Y));
    }
}

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于 2012-06-22T05:03:57.543 回答