我从 Google Talk 帐户收到消息，它们显示在 Ios 模拟器的表视图中，但是当我发送它时，它没有显示在 Google Talk 客户端（在另一台计算机上）中。这是代码：
-(IBAction)sendchat:(id)sender
{
General *general = [General sharedManager];//It is a singleton class used to store some values that need to be accesible in the whole application.
NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
text=[mensaje text];
NSLog(@"Texto en el body: %@", text);
[body setStringValue:text];
NSArray *dest=[general.firstfrom componentsSeparatedByString:@"/"];//in firstfrom is stored the account from wich we receive the first message. This app cannot start a conversation itself, must only answer
NSLog(@"Destination trimmed: %@", [dest objectAtIndex:0]);//Here, the destination account shows correctly (without the /xxxx stuff, just name@gmail.com)
XMPPMessage *mens=[[XMPPMessage alloc]init];
[mens addAttributeWithName:@"body" stringValue:text];
[mens addAttributeWithName:@"sender" stringValue:general.userlogin];
NSLog(@"text vale: %@", text);
NSXMLElement *messagetosend = [NSXMLElement elementWithName:@"message"];
[messagetosend addAttributeWithName:@"type" stringValue:@"chat"];
[messagetosend addAttributeWithName:@"to" stringValue:[dest objectAtIndex:0]];
[messagetosend addChild:body];
NSLog(@"We are sending to: %@", [dest objectAtIndex:0]);
[self.xmppStream sendElement:messagetosend];
[self xmppStream:xmppStream didReceiveMessage:mens];//manage the sent message as it was received, to show it in the Table View
self.mensaje.text=@"";
}
正如我所说，消息被完美接收，但我无法发送。我看过很多关于如何发送的例子，它们就像我的代码。如果我调试发件人，它显示正常（namesender@gmail.com），并且“to”属性也可以（namereceiver@gmail.com）。xmppStrem 设置正确（据我所知）：
xmppStream = [[XMPPStream alloc] init];
[xmppStream addDelegate:self delegateQueue:dispatch_get_main_queue()];
在 ViewDidLoad 方法中。
有什么帮助吗？谢谢你。
- -编辑 - -
我忘了说，两个帐户彼此认识，并且在 Google Talk 客户端中，发送状态。