iphone - 获取本地声明隐藏多个语句的实例变量警告消息

Question

我无法让这段代码工作。

在下面给出的语句上方声明了 playpauseButton

UIButton *playpauseButton = [UIButton buttonWithType:UIButtonTypeCustom];

playpauseButton获取以下语句的隐藏实例变量警告消息的本地声明

playpauseButton addTarget:self action:@selector(playpauseAction:) forControlEvents:UIControlEventTouchUpInside];
playpauseButton.frame = CGRectMake(0, 0, 30, 30);
[playpauseButton setImage:[UIImage imageNamed:@"Play Icon.png"] forState:UIControlStateNormal];
[playpauseButton setImage:[UIImage imageNamed:@"pause.png"] forState:UIControlStateSelected];
UIBarButtonItem *play = [[UIBarButtonItem alloc] initWithCustomView:playpauseButton];

在我定义之后playpauseAction method

-(void)playpauseAction:(id)sender {    
if( playpauseButton.state == UIControlStateNormal ){
    [sender setImage:[UIImage imageNamed:@"pause.png"] forState:UIControlStateSelected];
[audioPlayer play];
self.timer = [NSTimer scheduledTimerWithTimeInterval:11.0
                                    target:self
                                    selector:@selector(displayviewsAction:)
                                    userInfo:nil
                                    repeats:NO];
}  else if (playpauseButton.state == UIControlStateSelected)
{
[sender setImage:[UIImage imageNamed:@"Play Icon.png"] forState:UIControlStateNormal];
[audioPlayer pause];
 [self pauseTimer];
 } else if (playpauseButton.state == UIControlStateNormal)
{
[sender setImage:[UIImage imageNamed:@"pause.png"] forState:UIControlStateSelected];
[audioPlayer play];
[self resumeTimer];}}

请帮忙。

谢谢。

Answer 1

它告诉您，您有两个playpauseButton. 一个在类的接口部分（实例变量），另一个是局部变量。

这不是实际错误，但警告告诉您，您可能会得到与您想要的结果不同的结果。