iphone - 将非活动 UIView 捕获为 UIImage

Question

下面的代码运行良好，但只抓取屏幕上可见的 UIView。如何获取当前未显示的 UIView？

谢谢！

    //Take a screenshot of the view...
UIGraphicsBeginImageContext(View_1.frame.size);
    [View_1.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *View_1 = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
UIImageWriteToSavedPhotosAlbum(View_1, nil, nil, nil);

//...and attach it as an image to the email
NSData *myData3 = UIImagePNGRepresentation(View_1);
[picker addAttachmentData:myData3 mimeType:@"image/png" fileName:@"screenshot2"];   

Answer 1

如果您的意思是隐藏，view.hidden = YES;那么您将无法绘制它，而不是隐藏它，您可以将其从超级视图中删除，或者甚至view.hidden = NO;在绘制之前调用，然后在绘制view.hidden = YES;之后调用

例子

//Take a screenshot of the view...
UIGraphicsBeginImageContext(View_1.frame.size);
//Set it to visible
View_1.hidden = NO;
[View_1.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *View_1 = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
UIImageWriteToSavedPhotosAlbum(View_1, nil, nil, nil);
//Hide it again
View_1.hidden = YES;
//...and attach it as an image to the email
NSData *myData3 = UIImagePNGRepresentation(View_1);
[picker addAttachmentData:myData3 mimeType:@"image/png" fileName:@"screenshot2"];