使用此代码无法正确显示联系人的详细信息。我正在尝试使用Intent访问姓名、号码和电子邮件 ID。名称和号码仅在我单击按钮时显示，而不是电子邮件。项目中没有错误。它工作得很好。我的 xml 文件只有一个按钮。
公共类 GetDetails 扩展 Activity {
/** Called when the activity is first created. */
private static final int CONTACT_PICKER_RESULT = 1001;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button Btn = (Button)findViewById(R.id.getContacts);
Btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent i = new Intent(Intent.ACTION_PICK,ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(i, CONTACT_PICKER_RESULT);
}
});
}
protected void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);
if(resultCode == RESULT_OK) {
switch (reqCode) {
case CONTACT_PICKER_RESULT:
Cursor cursor = null;
Cursor emails = null;
String number = "";
String emailID = "";
try {
Uri result = data.getData();
//get the id from the uri
String id = result.getLastPathSegment();
//query
cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone._ID + " = ? " , new String[] {id}, null);
int numberIdx = cursor.getColumnIndex(Phone.DATA);
if(cursor.moveToFirst()) {
number = cursor.getString(numberIdx);
} else {
}
emails = getContentResolver().query(Email.CONTENT_URI,null,Email.CONTACT_ID + " = " + id, null, null);
int num = emails.getColumnIndex(Email.DATA);
if(emails.moveToFirst()) {
emailID = emails.getString(num);
} else {
}
} catch (Exception e) {
//failed
} finally {
if (cursor!=null) {
cursor.close();
}
}
}
}
}
}
如何解决这种情况？