我有一个 PHP 伺服器,它使用 CFB 模式解密 3DES 中的数据
我用 PHP 加密:
$montant = "500";
$message_crypte = mcrypt_encrypt(MCRYPT_3DES, "N4y1FRDRJ7wn7eJNnWaahCIS", $montant, ,CRYPT_MODE_CFB, "NCNPJDcR");
$montant = base64_encode($message_crypte);
PHP 中的此脚本适用于其他系统。
我想用 Java 加密:
public class CryptData {
private KeySpec keySpec;
private SecretKey key;
private IvParameterSpec iv;
public CryptData(String keyString, String ivString) {
try {
final MessageDigest md = MessageDigest.getInstance("md5");
final byte[] digestOfPassword = md.digest(Base64
.decodeBase64(keyString.getBytes("ISO-8859-1")));
final byte[] keyBytes = Arrays.copyOf(digestOfPassword, 24);
for (int j = 0, k = 16; j < 8;) {
keyBytes[k++] = keyBytes[j++];
}
//keySpec = new DESedeKeySpec(keyBytes);
keySpec = new DESedeKeySpec(keyString.getBytes());
key = SecretKeyFactory.getInstance("DESede")
.generateSecret(keySpec);
iv = new IvParameterSpec(ivString.getBytes());
} catch (Exception e) {
e.printStackTrace();
}
}
public String encrypt(String value) {
try {
Cipher ecipher = Cipher.getInstance("DESede/CFB/NoPadding");
//"SunJCE");
ecipher.init(Cipher.ENCRYPT_MODE, key, iv);
if (value == null)
return null;
// Encode the string into bytes using utf-8
byte[] valeur = value.getBytes("ISO-8859-1");
//byte[] utf8 = value.getBytes();
// Encrypt
byte[] enc = ecipher.doFinal(valeur);
// Encode bytes to base64 to get a string
return new String(Base64.encodeBase64(enc), "ISO-8859-1");
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
}
我在 PHP 和 Java 中的结果不同
如何修改Java处理以获得与PHP相同的结果?