iphone - 如何从 iOS 应用程序执行 URL 请求？

Question

我想向服务器发送以下请求。服务器已经知道如何处理它，但是我该如何发送呢？

http://www.********.com/ajax.php?script=logoutUser&username=****

Answer 1

对于同步请求，您将执行以下操作：

NSURL *url = [NSURL URLWithString:@"http://www.********.com/ajax.php?script=logoutUser&username=****"];
NSURLRequest *request = [NSURLRequest requestWithURL:url];

NSURLResponse *response;
NSError *error;
//send it synchronous
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
// check for an error. If there is a network error, you should handle it here.
if(!error)
{
    //log response
    NSLog(@"Response from server = %@", responseString);
}

更新：做一个异步请求请参考这个例子

Answer 2

你可以做：

NSString *resp = [NSString stringWithContentsOfURL:url usedEncoding:enc error: &error];