php - 寻找最大收入日

Question

我有一个包含以下字段的表收入

+----+-----------+-------------+---------------+
| id | member_id | amount_paid | datetime_paid |
+----+-----------+-------------+---------------+

我想运行查询以查找前 10 个最大收入天数。实现这一目标的最快方法是什么？该表有很多数据。

问候，

Answer 1

尝试执行它的基本查询：

SELECT DATE(`datetime_paid`) AS `Max Revenue`
    FROM `revenue`
    ORDER BY `amount_paid` DESC
    GROUP BY DATE(`datetime_paid`)
    LIMIT 10;

这向您显示了前 10 个最大付费天数。:)

Answer 2

假设您的datetime_paid列是某种日期或时间类型（请参阅 MySQL 文档），以下应该可以工作。

SELECT SUM( `amount_paid` ) AS `amount`, DATE( `datetime_paid` ) as `date`
  FROM yourTable
  GROUP BY `date`
  ORDER BY `amount` DESC
  LIMIT 10

Answer 3

首先，您需要按付款日期对结果进行分组。这可以通过选择DATE(datetime_paid) as payday，然后按 分组来完成payday。要获得总数，请选择SUM(amount_paid) as total。最后，要获得前 10 名，请按total desc和排序limit 10。

您的最终查询应如下所示：

SELECT DATE(`datetime_paid`) AS `payday`, SUM(`amount_paid`) AS `total`
FROM `table_name_here`
GROUP BY `payday`
ORDER BY `total` DESC
LIMIT 10

您可能需要将该ORDER BY行更改为ORDER BY SUM(amount_paid) DESC，我不记得在排序时是否允许使用字段别名。