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我正在尝试将几个参数传递给 SOAP 服务。我尝试在下面列出的代码块的最后执行此操作。出于某种原因,我无法让它工作。有人可以帮我一下吗。提前致谢!

    NSString *soapMessage = [NSString stringWithFormat:
                         @"<?xml version=\"1.0\" encoding=\"utf-8\"?>"
                         "<soap12:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap12=\"http://www.w3.org/2003/05/soap-envelope\">"
                         "<soap12:Body>"
                         "<UserLogin xmlns=\"http://tempuri.org/\">"
                         "<username>string</username>"
                         "<password>string</password>"
                         "</UserLogin>"
                         "</soap12:Body>"
                         "</soap12:Envelope>, %@, %@", txtUsername.text, txtPassword.text];
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1 回答 1

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NSString *soapMessage = [NSString stringWithFormat:
                         @"<?xml version=\"1.0\" encoding=\"utf-8\"?>"
                         "<soap12:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap12=\"http://www.w3.org/2003/05/soap-envelope\">"
                         "<soap12:Body>"
                         "<UserLogin xmlns=\"http://tempuri.org/\">"
                         "<username>%@</username>"
                         "<password>%@</password>"
                         "</UserLogin>"
                         "</soap12:Body>"
                         "</soap12:Envelope>", txtUsername.text, txtPassword.text];
于 2012-06-08T07:38:29.817 回答