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您好,我正在尝试将我的运算符重载>>到我的班级,但我在 Eclipse 中遇到错误。

代码:

    friend istream& operator>>(const istream& is, const RAngle& ra){
    return is >> ra.x >> ra.y;
}

代码2:

    friend istream& operator>>(const istream& is, const RAngle& ra)
{
    is >> ra.x;
    is >> ra.y;
    return is 
}

都崩溃了,我不知道为什么,请帮忙。

编辑:

ra.x&ra.y都是我班的 2 个私人整数;

完整错误:

错误:

   ..\/rightangle.h: In function 'std::istream& operator>>(std::istream&, const RAngle&)':
..\/rightangle.h:65:12: error: ambiguous overload for 'operator>>' in 'is >> ra.RAngle::x'
..\/rightangle.h:65:12: note: candidates are:
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:122:7: note: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>::__istream_type& (*)(std::basic_istream<_CharT, _Traits>::__istream_type&)) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:122:7: note:   no known conversion for argument 1 from 'const int' to 'std::basic_istream<char>::__istream_type& (*)(std::basic_istream<char>::__istream_type&) {aka std::basic_istream<char>& (*)(std::basic_istream<char>&)}'
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:126:7: note: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>::__ios_type& (*)(std::basic_istream<_CharT, _Traits>::__ios_type&)) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>, std::basic_istream<_CharT, _Traits>::__ios_type = std::basic_ios<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:126:7: note:   no known conversion for argument 1 from 'const int' to 'std::basic_istream<char>::__ios_type& (*)(std::basic_istream<char>::__ios_type&) {aka std::basic_ios<char>& (*)(std::basic_ios<char>&)}'
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:133:7: note: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(std::ios_base& (*)(std::ios_base&)) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:133:7: note:   no known conversion for argument 1 from 'const int' to 'std::ios_base& (*)(std::ios_base&)'
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:241:7: note: std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>::__streambuf_type*) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__streambuf_type = std::basic_streambuf<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:241:7: note:   no known conversion for argument 1 from 'const int' to 'std::basic_istream<char>::__streambuf_type* {aka std::basic_streambuf<char>*}'
..\/rightangle.h:66:12: error: ambiguous overload for 'operator>>' in 'is >> ra.RAngle::y'
..\/rightangle.h:66:12: note: candidates are:
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:122:7: note: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>::__istream_type& (*)(std::basic_istream<_CharT, _Traits>::__istream_type&)) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:122:7: note:   no known conversion for argument 1 from 'const int' to 'std::basic_istream<char>::__istream_type& (*)(std::basic_istream<char>::__istream_type&) {aka std::basic_istream<char>& (*)(std::basic_istream<char>&)}'
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:126:7: note: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>::__ios_type& (*)(std::basic_istream<_CharT, _Traits>::__ios_type&)) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>, std::basic_istream<_CharT, _Traits>::__ios_type = std::basic_ios<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:126:7: note:   no known conversion for argument 1 from 'const int' to 'std::basic_istream<char>::__ios_type& (*)(std::basic_istream<char>::__ios_type&) {aka std::basic_ios<char>& (*)(std::basic_ios<char>&)}'
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:133:7: note: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(std::ios_base& (*)(std::ios_base&)) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:133:7: note:   no known conversion for argument 1 from 'const int' to 'std::ios_base& (*)(std::ios_base&)'
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:241:7: note: std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>::__streambuf_type*) [with _CharT = char, _Traits = std::char_traits<char>, std::basic_istream<_CharT, _Traits>::__streambuf_type = std::basic_streambuf<char>] <near match>
c:\mingw\bin\../lib/gcc/mingw32/4.6.1/include/c++/istream:241:7: note:   no known conversion for argument 1 from 'const int' to 'std::basic_istream<char>::__streambuf_type* {aka std::basic_streambuf<char>*}''
4

3 回答 3

2

一个问题在于操作员的签名:

friend istream& operator>>(const istream& is, const RAngle& ra){
//                         ^^^^^              ^^^^^
    return is >> ra.x >> ra.y;
}

如果参数是,const您将无法修改它们。从错误消息来看,它们似乎表明编译器无法为is >> ra.xand找到适当的重载is >> ra.y。这可能与上一个问题(找不到采用 const-lvalue 的重载)或不相关,具体取决于ra.xand的类型ra.y(问题中未显示)。

于 2012-06-04T16:42:17.610 回答
2

因为operator>>要修改你传递给它的参数,它们不能是对 const 的引用,所以你想要的是这样的:

friend std::istream &operator>>(std::istream &is, RAngle &ra) { 
    return is >> ra.x >> ra.y;
}

请注意,几乎所有 I/O 操作也(至少可能)更改流的状态,因此您(几乎?)总是希望通过非常量引用传递流参数。

于 2012-06-04T16:42:18.523 回答
1

请从参数“const RANgle& ra”中删除 const。您不能修改方法中的常量引用。

于 2012-06-04T16:40:31.553 回答