目前我正在通过 SOAP 方法使用来自 android 的 Web 服务。这里我需要调用 Web 服务并在 android/eclipse.ie 上返回结果。我需要从 edittext 获取输入并返回适当的值。
请找到我的代码以供参考。
网络方法
public class GetName {
public String GetName(String a){
return(a);
} }
注意： 为了避免来自主活动线程的套接字操作异常，我编写了一个单独的类并隔离了与肥皂相关的函数。
调用者.java
public class Caller extends Thread
{
public AlertDialog ad;
public CallSoap cs;
public int a;
public void run()
{
try
{
cs=new CallSoap();
String resp=cs.Call(a);
MySOAPCallActivity.rslt=resp;
}catch(Exception ex)
{
MySOAPCallActivity.rslt=ex.toString();
}
} }
调用SOAP
public class CallSoap
{
public final String SOAP_ACTION = "http://tempuri.org/GetName";
public final String OPERATION_NAME = "GetName";
public final String WSDL_TARGET_NAMESPACE = "http://tempuri.org/";
public final String SOAP_ADDRESS = "http://122.248.240.105:234/Service1.asmx?WSDL";
public CallSoap()
{
}
public String Call(int a)
{
SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
PropertyInfo pi=new PropertyInfo();
pi.setName("a");
pi.setValue(a);
pi.setType(Integer.class);
request.addProperty(pi);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS);
Object response=null;
try
{
httpTransport.call(SOAP_ACTION, envelope);
response = envelope.getResponse();
}
catch (Exception exception)
{
response=exception.toString();
}
return response.toString();
}
}
MySOAPCallActivity
public class MySOAPCallActivity extends Activity
{
public static String rslt="";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button b1=(Button)findViewById(R.id.btn_getvalues);
final AlertDialog ad=new AlertDialog.Builder(this).create();
b1.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
try
{
EditText ed1=(EditText)findViewById(R.id.et_1);
String ed1str = ed1.getText().toString().trim();
int a = Integer.parseInt(ed1str);
rslt="START";
Caller c=new Caller();
c.a=a;
c.ad=ad;
c.join();
c.start();
while(rslt=="START")
{
try
{
Thread.sleep(5);
}catch(Exception ex)
{
}
}
ad.setTitle("");
ad.setMessage(rslt);
}catch(Exception ex)
{
ad.setTitle("Error!");
ad.setMessage(ex.toString());
}
ad.show();
}
});
} }
输出屏幕
注意：如果我输入值“0005” ，它必须在浏览器中返回字符串“Vivek” 。
但在我的输出屏幕中，它显示为“未找到名称”。我想根据用户输入返回适当的值。请让我知道如何修改我的来源。
感谢您宝贵的时间！..