2

正如标题所说，我无法找到我想要的控件。

这是网格视图：

    <asp:GridView ID="gvInfo" runat="server" AutoGenerateColumns="false" AutoGenerateEditButton="true">
        <Columns>
            <asp:BoundField DataField="filename" HeaderText="Filename" SortExpression="filename" />
            <asp:ButtonField ButtonType="Button" CommandName="Select" 
                HeaderText="Move File" ShowHeader="True" Text="Move File" />
        </Columns>
    </asp:GridView>

这是后面的代码：

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
    If Not IsPostBack Then
        ShowGV()
    End If
End Sub

Protected Sub gvInfo_RowEditing(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewEditEventArgs) Handles gvInfo.RowEditing
    gvInfo.EditIndex = e.NewEditIndex
    ShowGV()
End Sub

Protected Sub gvInfo_RowCancelingEdit(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewCancelEditEventArgs) Handles gvInfo.RowCancelingEdit
    gvInfo.EditIndex = -1
    ShowGV()
End Sub

Protected Sub gvInfo_RowUpdating(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewUpdateEventArgs) Handles gvInfo.RowUpdating
    Dim row = gvInfo.Rows(e.RowIndex)
    Dim Test As String = CType(row.FindControl("filename"), TextBox).Text
    Response.Write(Test)

    gvInfo.EditIndex = -1
    ShowGV()
End Sub

任何帮助深表感谢。

谢谢。

4

1 回答 1

2

尝试

CType(row.Cells(0).Controls(0), TextBox).Text
'change index of `cell(0)` to required column index (column index starts from 0)

或者

将所需列转换为 aTemplateField并使用，

CType(row.FindControl("LabelNamein'EditItemTemplate'"), TextBox).Text
于 2012-06-01T05:07:02.680 回答