mysql - 具有相同列的 MSQL 连接表

Question

我环顾四周，找不到答案。可能是我不知道要寻找的正确术语。

我有大约 15 个表，所有表都有相同的列和相似的数据。它们之间的唯一区别是创建日期。

我想像这样搜索其中一些：

SELECT * 
FROM table_2010, table_2011 
WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01'
ORDER BY date_created

但我不相信这会起作用，因为它将我的所有数据视为 2 个表，并创建模棱两可的字段：P

有什么建议么？这是工会工作还是什么？！

Answer 1

select * 
from (SELECT * FROM table_2010
      WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01'
      union
      SELECT * FROM table_2011
      WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01'
) as t
ORDER BY date_created

Answer 2

创建表对象，试试这个

SELECT * 
FROM table_2010 AS t1, table_2011 AS t2
WHERE ( t1.date_created BETWEEN '2010-04-01' AND '2011-04-01' AND t2.date_created BETWEEN '2010-04-01' AND '2011-04-01')
ORDER BY t1.date_created,t2.date_created

Answer 3

这是一个联合，但您需要从联合中进行选择以获取跨表的顺序，但如果 date_created 始终在表的年份，您可能可以跳过该步骤

Select * From (
SELECT *  FROM table_2010
WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01'
Union all
Select * From Table_2010
WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01'
) allmyTables
ORDER BY date_created 

Answer 4

使用别名'

SELECT * 
FROM table_2010 as t2010, table_2011 as t2011 
WHERE t2010.date_created BETWEEN '2010-04-01' AND '2011-04-01'
ORDER BY t2010.date_created

Answer 5

尝试这个

SELECT table_2010.*, table_2011.* 
FROM table_2010, table_2011 
WHERE table_2010.date_created >= '2010-04-01' AND table_2011.date_created <= '2011-04-01'
ORDER BY table_2010.date_created, table_2011.date_created

我相信 2010 表中只有 2010 年的数据，而 2011 年表中只有 2011 年的数据。

Answer 6

SELECT *  FROM table_2010 
WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01' ORDER BY date_created 

union

SELECT *  FROM table_2011 
WHERE date_created BETWEEN '2010-04-01' AND '2011-04-01' ORDER BY date_created