我有一个这样的音频文件列表,
int music_numbers[] = { R.raw.one, R.raw.two, R.raw.three, R.raw.four,
R.raw.five, R.raw.six, R.raw.seven, R.raw.eight, R.raw.nine };
我需要一个一个地玩这个——当我向这个 play_numbers 方法发送 100 时——我打算明智地玩数字..
我已经做到了 - 但我无法一个接一个地做到这一点..
private void _play_numbers(final String i) {
// TODO Auto-generated method stub
mPlayer = MediaPlayer.create(PlayFileActivity.this, R.raw.payment);
mPlayer.start();
mPlayer.setOnCompletionListener(new OnCompletionListener() {
@Override
public void onCompletion(MediaPlayer mp) {
// TODO Auto-generated method stub
mPlayer.stop();
myDigit = i.charAt(1) + "";
_function_play_file(Integer.parseInt(myDigit));
}
});
}
在 _function_play_file - 我有这个
void _function_play_file(int files) {
switch (files) {
case 0:
mPlayer = MediaPlayer.create(this, music_numbers[0]);
mPlayer.start();
case 1:
mPlayer = MediaPlayer.create(this, music_numbers[1]);
mPlayer.start();
case 2:
mPlayer = MediaPlayer.create(this, music_numbers[2]);
mPlayer.start();
case 3:
mPlayer = MediaPlayer.create(this, music_numbers[3]);
mPlayer.start();
case 4:
mPlayer = MediaPlayer.create(this, music_numbers[4]);
mPlayer.start();
case 5:
mPlayer = MediaPlayer.create(this, music_numbers[5]);
mPlayer.start();
case 6:
mPlayer = MediaPlayer.create(this, music_numbers[6]);
mPlayer.start();
case 7:
mPlayer = MediaPlayer.create(this, music_numbers[7]);
mPlayer.start();
case 8:
mPlayer = MediaPlayer.create(this, music_numbers[8]);
mPlayer.start();
case 9:
mPlayer = MediaPlayer.create(this, music_numbers[9]);
mPlayer.start();
case 10:
mPlayer = MediaPlayer.create(this, music_numbers[10]);
mPlayer.start();
}
}