1

此代码有什么问题或可能导致此问题的原因是什么？它没有提醒“你好”，但它正在用 Hello 和 Bye World 表填充 div。我希望它提醒“你好”。我也不知道jquery。谢谢你

文件1

var xmlhttp;
if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }else{// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function(){
  if (xmlhttp.readyState==4 && xmlhttp.status==200){
     var reScript = /\<script.*?>(.*)<\/script>/mg;
     response = xmlhttp.responseText.replace(reScript, function(m,m1) {
     eval(m1);
     return "";
     });
    document.getElementById("div").innerHTML=response;
    }
  }
xmlhttp.open('GET','file2.php',true);
xmlhttp.setRequestHeader('Content-type','application/x-www-form-urlencoded');
xmlhttp.send();

文件2

  <table><tr><td>Hello World</td></tr></table>
  <script type="text/javascript">
  alert('hello');
  </script>
  <table><tr><td>Bye World</td></tr></table>
4

2 回答 2

2

尝试不使用eval()：

var xmlhttp;
if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }else{// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function(){
  if (xmlhttp.readyState==4 && xmlhttp.status==200){
     /*var reScript = /\<script.*?>(.*)<\/script>/mg;
     response = xmlhttp.responseText.replace(reScript, function(m,m1) {
     eval(m1);
     return "";
     });*/
    document.getElementById("div").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open('GET','file2.php',true);
//xmlhttp.setRequestHeader('Content-type','application/x-www-form-urlencoded'); //unnecessary for GET calls
xmlhttp.send(null);

Eval使用您的代码<script...></script>是不必要的，javascript 代码将在添加到 DOM 后立即执行。

新编辑：

您必须消除\n\rreponseText 中的换行符才能eval正确使用您的脚本。\此外，在第一个转义字符之前还有一个额外的转义字符，<它破坏了您的代码。尝试：

var xmlhttp;
if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }else{// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function(){
  if (xmlhttp.readyState==4 && xmlhttp.status==200){
     var reScript = /<script.*?>(.*)<\/script>/mg;
     response = xmlhttp.responseText.replace(/\n|\r/g, " ").replace(reScript, function(m,m1) {
     eval(m1);
     return "";
     });
    document.getElementById("div").innerHTML=response;
    }
  }
xmlhttp.open('GET','file2.php',true);
//xmlhttp.setRequestHeader('Content-type','application/x-www-form-urlencoded');
xmlhttp.send(null);

I've added a .replace(/\n|\r/g, " ") to replace all line breaks by an white space in your responseText, which will allow for your JS to be evaluated properly and cause no visible change to the end-user. You may also replace the white space " " by an empty string "" if all of your JS is properly semi-colon'd.

The above should work fine for simple scripts, now if you'd include the JQuery lib in your page's head:

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

Your AJAX call would be as simple as:

<script type="text/javascript">
$(document).ready(function(){
    $('#div').load('file2.php');
});
</script>

JQuery automatically parses scripts from your responseText, as noted in your linked answer.

于 2012-05-27T02:15:07.347 回答
0

Give this a try:

xmlhttp.onreadystatechange=function(){
  if (xmlhttp.readyState==4 && xmlhttp.status==200){
    var reScript = /<script.*?\>(.*)<\/script\>/mg.exec(xmlhttp.responseText)[1];
    var scriptElement = document.createElement('script');
    scriptElement.innerHTML = reScript;
    document.body.appendChild(scriptElement);
  }
}

Placing the code into a script element, and then appending that element to the body should cause it to execute.

于 2012-05-27T02:33:49.087 回答