php - PHP将值传递给类

Question

我有一个名为 DatabaseController 的类，我已将其设置为：

<?php

class DBController {

    public $dbName;

    function _controller($passedDBName) { 
        $dbName = $passedDBName;
    }

    function dbConnect() { 
        print $this->$dbName;
    }



} //end of class       
?>

我这样称呼它：

<?php

    //make new database connection
    $dbManager = new DBController("somevalue");
    $dbManager->dbConnect();


?>

但我不断收到此错误：

<b>Fatal error</b>:  Cannot access empty property in 

我究竟做错了什么？

谢谢

Answer 1

在构造函数中，$dbName = $passedDBName;应该是$this->dbName = $passedDBName;.

更新：

1. $this->$dbName应该是$this->dbName。
2. _controller()应该是__construct()。

Answer 2

使用$this->dbName- 否则您将尝试访问名称存储在$dbName. 您还需要修复您的构造函数以分配给$this->dbName而不是$dbName.

class DBController {
    public $dbName;
    function _controller($passedDBName) { 
        $this->dbName = $passedDBName;
    }
    function dbConnect() { 
        print $this->dbName;
    }
}