13

使用谷歌模拟对象编写（谷歌）测试用例并期望从测试中的类控制的另一个线程调用 EXPECT_CALL() 定义的最佳方法是什么？在触发调用序列后简单地调用 sleep() 或类似方法并不合适，因为它可能会减慢不必要的测试并且可能不会真正达到计时条件。但是以某种方式完成测试用例必须等到模拟方法被调用。任何人的想法？

下面是一些代码来说明这种情况：

Bar.hpp（被测类）

class Bar
{
public:

Bar(IFooInterface* argFooInterface);
virtual ~Bar();

void triggerDoSomething();
void start();
void stop();

private:
void* barThreadMethod(void* userArgs);
void endThread();
void doSomething();

ClassMethodThread<Bar> thread; // A simple class method thread implementation using boost::thread
IFooInterface* fooInterface;
boost::interprocess::interprocess_semaphore semActionTrigger;
boost::interprocess::interprocess_semaphore semEndThread;
bool stopped;
bool endThreadRequested;
};

Bar.cpp（摘录）：

void Bar::triggerDoSomething()
{
    semActionTrigger.post();
}

void* Bar::barThreadMethod(void* userArgs)
{
    (void)userArgs;
    stopped = false;
    do
    {
        semActionTrigger.wait();
        if(!endThreadRequested && !semActionTrigger.try_wait())
        {
            doSomething();
        }
    } while(!endThreadRequested && !semEndThread.try_wait());
    stopped = true;
    return NULL;
}

void Bar::doSomething()
{
    if(fooInterface)
    {
        fooInterface->func1();
        if(fooInterface->func2() > 0)
        {
            return;
        }
        fooInterface->func3(5);
    }
}

测试代码（摘录，到目前为止 FooInterfaceMock 的定义没有什么特别之处）：

class BarTest : public ::testing::Test
{
public:

    BarTest()
    : fooInterfaceMock()
    , bar(&fooInterfaceMock)
    {
    }

protected:
    FooInterfaceMock fooInterfaceMock;
    Bar bar;
};

TEST_F(BarTest, DoSomethingWhenFunc2Gt0)
{
    EXPECT_CALL(fooInterfaceMock,func1())
        .Times(1);
    EXPECT_CALL(fooInterfaceMock,func2())
        .Times(1)
        .WillOnce(Return(1));

    bar.start();
    bar.triggerDoSomething();
    //sleep(1);
    bar.stop();
}

没有 sleep() 的测试结果：

[==========] Running 1 test from 1 test case.
[----------] Global test environment set-up.
[----------] 1 test from BarTest
[ RUN      ] BarTest.DoSomethingWhenFunc2Gt0
../test/BarTest.cpp:39: Failure
Actual function call count doesn't match EXPECT_CALL(fooInterfaceMock, func2())...
         Expected: to be called once
           Actual: never called - unsatisfied and active
../test/BarTest.cpp:37: Failure
Actual function call count doesn't match EXPECT_CALL(fooInterfaceMock, func1())...
         Expected: to be called once
           Actual: never called - unsatisfied and active
[  FAILED  ] BarTest.DoSomethingWhenFunc2Gt0 (1 ms)
[----------] 1 test from BarTest (1 ms total)

[----------] Global test environment tear-down
[==========] 1 test from 1 test case ran. (1 ms total)
[  PASSED  ] 0 tests.
[  FAILED  ] 1 test, listed below:
[  FAILED  ] BarTest.DoSomethingWhenFunc2Gt0

 1 FAILED TEST
terminate called after throwing an instance of         'boost::exception_detail::clone_impl<boost::exception_detail::error_info_injector<boost::lock_error> >'
Aborted

启用 sleep() 的测试结果：

[==========] Running 1 test from 1 test case.
[----------] Global test environment set-up.
[----------] 1 test from BarTest
[ RUN      ] BarTest.DoSomethingWhenFunc2Gt0
[       OK ] BarTest.DoSomethingWhenFunc2Gt0 (1000 ms)
[----------] 1 test from BarTest (1000 ms total)

[----------] Global test environment tear-down
[==========] 1 test from 1 test case ran. (1000 ms total)
[  PASSED  ] 1 test.

我想避免 sleep()，最好的情况是根本不需要更改 Bar 类。

4

5 回答 5

15

弗雷泽的回答启发了我使用 GMock 专用动作的简单解决方案。GMock 使得快速编写此类动作变得非常容易。

这是代码（摘自 BarTest.cpp）：

// Specialize an action that synchronizes with the calling thread
ACTION_P2(ReturnFromAsyncCall,RetVal,SemDone)
{
    SemDone->post();
    return RetVal;
}

TEST_F(BarTest, DoSomethingWhenFunc2Gt0)
{
    boost::interprocess::interprocess_semaphore semDone(0);
    EXPECT_CALL(fooInterfaceMock,func1())
        .Times(1);
    EXPECT_CALL(fooInterfaceMock,func2())
        .Times(1)
        // Note that the return type doesn't need to be explicitly specialized
        .WillOnce(ReturnFromAsyncCall(1,&semDone));

    bar.start();
    bar.triggerDoSomething();
    boost::posix_time::ptime until = boost::posix_time::second_clock::universal_time() +
            boost::posix_time::seconds(1);
    EXPECT_TRUE(semDone.timed_wait(until));
    bar.stop();
}

TEST_F(BarTest, DoSomethingWhenFunc2Eq0)
{
    boost::interprocess::interprocess_semaphore semDone(0);
    EXPECT_CALL(fooInterfaceMock,func1())
        .Times(1);
    EXPECT_CALL(fooInterfaceMock,func2())
        .Times(1)
        .WillOnce(Return(0));
    EXPECT_CALL(fooInterfaceMock,func3(Eq(5)))
        .Times(1)
        // Note that the return type doesn't need to be explicitly specialized
        .WillOnce(ReturnFromAsyncCall(true,&semDone));

    bar.start();
    bar.triggerDoSomething();
    boost::posix_time::ptime until = boost::posix_time::second_clock::universal_time() +
            boost::posix_time::seconds(1);
    EXPECT_TRUE(semDone.timed_wait(until));
    bar.stop();
}

请注意，相同的原则对于任何其他类型的信号量实现都适用，如boost::interprocess::interprocess_semaphore. 我用它来测试我们的生产代码，这些代码使用它自己的操作系统抽象层和信号量实现。

于 2012-05-28T10:36:31.083 回答
7

使用 lambdas，您可以执行以下操作（我已在评论中添加了 boost 等价物）：

TEST_F(BarTest, DoSomethingWhenFunc2Gt0)
{
    std::mutex mutex;                  // boost::mutex mutex;
    std::condition_variable cond_var;  // boost::condition_variable cond_var;
    bool done(false);

    EXPECT_CALL(fooInterfaceMock, func1())
        .Times(1);
    EXPECT_CALL(fooInterfaceMock, func2())
        .Times(1)
        .WillOnce(testing::Invoke([&]()->int {
            std::lock_guard<std::mutex> lock(mutex);  // boost::mutex::scoped_lock lock(mutex);
            done = true;
            cond_var.notify_one();
            return 1; }));

    bar.start();
    bar.triggerDoSomething();
    {
      std::unique_lock<std::mutex> lock(mutex);               // boost::mutex::scoped_lock lock(mutex);
      EXPECT_TRUE(cond_var.wait_for(lock,                     // cond_var.timed_wait
                                    std::chrono::seconds(1),  // boost::posix_time::seconds(1),
                                    [&done] { return done; }));
    }
    bar.stop();
}

如果你不能使用 lambdas，我想你可以boost::bind改用。

于 2012-05-27T19:23:22.773 回答
3

所以我喜欢这些解决方案，但我认为通过 promise 可能会更容易，我不得不等待我的测试启动：

std::promise<void> started;
EXPECT_CALL(mock, start_test())
    .Times(1)
    .WillOnce(testing::Invoke([&started]() {
        started.set_value();
    }));
system_->start();
EXPECT_EQ(std::future_status::ready, started.get_future().wait_for(std::chrono::seconds(3)));
于 2019-07-09T11:26:55.230 回答
0

弗雷泽的回答也启发了我。我使用了他的建议，它奏效了，但后来我找到了另一种没有条件变量的方法来完成同样的任务。您需要添加一个方法来检查某些条件，并且您需要一个无限循环。这也假设您有一个单独的线程来更新条件。

TEST_F(BarTest, DoSomethingWhenFunc2Gt0)
{
    EXPECT_CALL(fooInterfaceMock,func1()).Times(1);
    EXPECT_CALL(fooInterfaceMock,func2()).Times(1).WillOnce(Return(1));

    bar.start();
    bar.triggerDoSomething();

    // How long of a wait is too long?
    auto now = chrono::system_clock::now();
    auto tooLong = now + std::chrono::milliseconds(50); 

    /* Expect your thread to update this condition, so execution will continue
     * as soon as the condition is updated and you won't have to sleep
     * for the remainder of the time
     */
    while (!bar.condition() && (now = chrono::system_clock::now()) < tooLong) 
    {
        /* Not necessary in all cases, but some compilers may optimize out
         * the while loop if there's no loop body.
         */
        this_thread::sleep_for(chrono::milliseconds(1));
    }

    // If the assertion fails, then time ran out.  
    ASSERT_LT(now, tooLong);

    bar.stop();
}
于 2016-10-27T14:30:51.577 回答
0

在 πάντα ῥεῖ 解决方案提出后，我设法解决了这个问题，但使用了 std::condition_variable。该解决方案与 Fraser 提出的方案有些不同，也可以使用 lambdas 进行改进。

ACTION_P(ReturnFromAsyncCall, cv)
{
    cv->notify_all();
}

...

TEST_F(..,..)
{

   std::condition_variable cv;
   ...
   EXPECT_CALL(...).WillRepeatedly(ReturnFromAsyncCall(&cv));

   
   std::mutex mx;
   std::unique_lock<std::mutex> lock(mx);
   cv.wait_for(lock, std::chrono::seconds(1));
   
 }

似乎互斥锁只是为了满足条件变量。

于 2020-07-31T15:33:33.217 回答