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我的项目有许多包（“模型”、“控制器”等）。我已经使用 Cobertura 插件设置了 Jenkins 以生成覆盖率报告，这很棒。如果覆盖率低于某个阈值，我想将构建标记为不稳定，但仅限于某些包（例如，“控制器”，而不是“模型”）。但是，我在配置 UI 中没有看到明显的方法来执行此操作——看起来阈值是全局的。

有没有办法做到这一点？

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1 回答 1

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（在这里回答我自己的问题）

据我所知，这是不可能的——看了几天后我什么也没看到。我写了一个简单的脚本来做我想做的事——获取覆盖输出，解析它，如果特定包的覆盖不满足某些阈值，则构建失败。它很脏，可以清理/扩展，但基本思想就在这里。欢迎评论。

#!/usr/bin/env python

'''
Jenkins' Cobertura plugin doesn't allow marking a build as successful or
failed based on coverage of individual packages -- only the project as a
whole. This script will parse the coverage.xml file and fail if the coverage of
specified packages doesn't meet the thresholds given

'''

import sys

from lxml import etree

PACKAGES_XPATH = etree.XPath('/coverage/packages/package')


def main(argv):
    filename = argv[0]
    package_args = argv[1:] if len(argv) > 1 else []
    # format is package_name:coverage_threshold
    package_coverage = {package: int(coverage) for
        package, coverage in [x.split(':') for x in package_args]}

    xml = open(filename, 'r').read()
    root = etree.fromstring(xml)

    packages = PACKAGES_XPATH(root)

    failed = False
    for package in packages:
        name = package.get('name')
        if name in package_coverage:
            # We care about this one
            print 'Checking package {} -- need {}% coverage'.format(
                name, package_coverage[name])
            coverage = float(package.get('line-rate', '0.0')) * 100
            if coverage < package_coverage[name]:
                print ('FAILED - Coverage for package {} is {}% -- '
                       'minimum is {}%'.format(
                        name, coverage, package_coverage[name]))
                failed = True
            else:
                print "PASS"

    if failed:
        sys.exit(1)

if __name__ == '__main__':
    main(sys.argv[1:])
于 2012-05-30T01:24:27.013 回答