2

我在互联网上搜索并学习了其他实现它的方法，现在我发现了这个问题。如果我在 subprocess.Popen 中写入 stdout=subprocess.PIPE，我的执行时间总是会超过超时时间。如果我要删除它，那么它需要正常的执行时间

import subprocess, datetime, os, time, signal
//setting time for timeout
timeout=3
start = datetime.datetime.now()
process = subprocess.Popen(["python", "/home/bourne/untitled.py"],shell=False, stdout=subprocess.PIPE,stderr=subprocess.PIPE)
while process.poll() is None:
        time.sleep(0.1)
        now = datetime.datetime.now()
        if (now - start).seconds > timeout:
            os.kill(process.pid, signal.SIGKILL)
            os.waitpid(-1, os.WNOHANG)
            print "error"       
            print (now - start).seconds
            break
        print (now - start).seconds
4

3 回答 3

3

您不应该仅仅因为它在 5 秒内超时而产生一个新线程，然后将它的isAlive状态用作忙等待的中断条件。你不需要额外的线程，你可以在第一个线程中弄乱时间。

与其尽可能频繁地轮询线程，不如使用延迟 ( time.sleep) 来让处理器做一些实际的工作。

而且您应该知道，如果您的进程正在生成大量输出，如果您在进程执行时不读取它，它将阻塞并让它填满管道的缓冲区。

于 2012-05-24T09:01:20.697 回答
0

线程可以在 python VM 中处理，但不能处理。所以你必须使用 OS api 来杀死你的进程/子进程，例如（在 linux 中）：

os.system("kill -9 %s"%(proc.pid))

而且，使用线程进行计时是一个坏主意。怎么样：

start_t = time.time()
TIME_END, TIME_SLEEP = 5, 1
while time.time() - start_t < TIME_END:
    if proc.poll():
        break
    time.sleep(TIME_SLEEP)
于 2012-05-24T09:14:02.563 回答
0 
I have successfully solved the problem. the solution is 

import subprocess, signal, os, threading, errno
from contextlib import contextmanager

class TimeoutThread(object):
    def __init__(self, seconds):
        self.seconds = seconds
        self.cond = threading.Condition()
        self.cancelled = False
        self.thread = threading.Thread(target=self._wait)

    def run(self):
        """Begin the timeout."""
        self.thread.start()

    def _wait(self):
        with self.cond:
            self.cond.wait(self.seconds)

            if not self.cancelled:
                self.timed_out()

    def cancel(self):
        """Cancel the timeout, if it hasn't yet occured."""
        with self.cond:
            self.cancelled = True
            self.cond.notify()
        self.thread.join()

    def timed_out(self):
        """The timeout has expired."""
        raise NotImplementedError

class KillProcessThread(TimeoutThread):
    def __init__(self, seconds, pid):
        super(KillProcessThread, self).__init__(seconds)
        self.pid = pid

    def timed_out(self):
        try:
            os.kill(self.pid, signal.SIGKILL) // this is for linux you need to change it for windows
        except OSError,e:
            # If the process is already gone, ignore the error.
            if e.errno not in (errno.EPERM, errno. ESRCH):
                raise e

@contextmanager
def processTimeout(seconds, pid):
    timeout = KillProcessThread(seconds, pid)
    timeout.run()
    try:
        yield
    finally:
        timeout.cancel()


def example(cmd):
    proc = subprocess.Popen(cmd, stderr=subprocess.PIPE, stdout=subprocess.PIPE)
    //setting the timeout to be 1 sec
    with processTimeout(1, proc.pid):
        stdout,stderr=proc.communicate()       

    resultcode = proc.wait()
    if resultcode &lt; 0:
        #print "error: %i" % resultcode
        return resultcode,0
    else:
        return stdout,stderr





//This is used to create new subprocess and it will return output as well as error
output,err=example(["python",filepath,"5"])
于 2012-07-21T06:43:20.583 回答