26

我已经配置了两个持久单元，其实体管理器设置如下所示：

<bean id="liveEntityManagerFactory" 
          class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
          p:dataSource-ref="LiveDataSource">          

          <property name="persistenceUnitName" value="LivePersistenceUnit" />
    </bean>

    <bean id="archiveEntityManagerFactory" 
          class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
          p:dataSource-ref="ArchiveDataSource">          

          <property name="persistenceUnitName" value="ArchivePersistenceUnit" />
    </bean>

然后我将事务管理器配置为

 <bean id="LiveTransactionManager"
          class="org.springframework.orm.jpa.JpaTransactionManager"
          p:entityManagerFactory-ref="liveEntityManagerFactory"/>

    <bean id="ArchiveTransactionManager"
          class="org.springframework.orm.jpa.JpaTransactionManager"
          p:entityManagerFactory-ref="archiveEntityManagerFactory"/>

我最初只配置了一个，它被称为“transactionManager”。添加一个额外的持久单元似乎会产生错误。我不明白的一件事是，如果我配置了两个持久单元（每个用于一个单独的数据库），我是否还需要为每个数据源配置一个单独的实体管理器和一个事务管理器？

我得到的错误如下所示：（我搜索了所有文件，但在任何有“transactionManager”引用的地方都找不到）

org.springframework.ws.soap.client.SoapFaultClientException: No bean named 'transactionManager' is defined
    at org.springframework.ws.soap.client.core.SoapFaultMessageResolver.resolveFault(SoapFaultMessageResolver.java:37)
    at org.springframework.ws.client.core.WebServiceTemplate.handleFault(WebServiceTemplate.java:774)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:600)
    at org.springframework.ws.client.core.WebServiceTemplate.sendAndReceive(WebServiceTemplate.java:537)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:384)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:378)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:370)
    at com.ws.client.SoapTest.testFail(SoapTest.java:140)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
    at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:74)
    at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
    at org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:83)
    at org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:72)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:231)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:46)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:180)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:41)
    at org.junit.runners.ParentRunner$1.evaluate(ParentRunner.java:173)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
    at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
    at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:71)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:220)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:174)
    at org.apache.maven.surefire.junit4.JUnit4TestSet.execute(JUnit4TestSet.java:53)
    at org.apache.maven.surefire.junit4.JUnit4Provider.executeTestSet(JUnit4Provider.java:123)
    at org.apache.maven.surefire.junit4.JUnit4Provider.invoke(JUnit4Provider.java:104)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.apache.maven.surefire.util.ReflectionUtils.invokeMethodWithArray(ReflectionUtils.java:164)
    at org.apache.maven.surefire.booter.ProviderFactory$ProviderProxy.invoke(ProviderFactory.java:110)
    at org.apache.maven.surefire.booter.SurefireStarter.invokeProvider(SurefireStarter.java:175)
    at org.apache.maven.surefire.booter.SurefireStarter.runSuitesInProcessWhenForked(SurefireStarter.java:107)
    at org.apache.maven.surefire.booter.ForkedBooter.main(ForkedBooter.java:68)

我正在将 Spring 与 Jpa/Hibernate 一起使用。

谢谢

4

4 回答 4

26

事务管理器属性的默认值为事务管理器。在您的情况下，您应该指定每个方法或服务要使用的事务管理器，如下所示：

@Service
@Transactional(value="LiveTransactionManager") 
class someClass...

或者

@Transactional(value="ArchiveTransactionManager") 
public void someMethod
于 2012-05-23T12:46:48.573 回答
8

实际上，有一种方法可以将命名的 TransactionManager 与 Spring Data JPA 一起使用。这对我有用：

<bean id="myTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="myEntityManagerFactory" />
</bean>
<tx:annotation-driven transaction-manager="myTransactionManager"/>

<jpa:repositories base-package="com.xxx.yyy" entity-manager-factory-ref="myEntityManagerFactory" transaction-manager-ref="myTransactionManager">
</jpa:repositories>
于 2014-01-25T08:42:05.957 回答
2

我使用 java 配置并指定transactionManagerRef是我的解决方案：

@Configuration
@EnableTransactionManagement
@EnableJpaRepositories(
    entityManagerFactoryRef = "myCustomEntityManagerFactory",
    basePackages = {"ua.demitt.other.path.to.repos"},
    transactionManagerRef = "myCustomTransactionManager" )
于 2019-04-23T20:04:50.133 回答
0

在您的 @Configuration 文件中，如果这是您的数据源：

@Bean(name = "dataSource")
public DataSource getDataSource() {
    return DataSourceBuilder
            .create()
            .username(username)
            .password(password)
            .url(url)
            .build();
}

这将是您的事务管理器 bean：

@Bean(name = "DataSourceTransactionManager")
public DataSourceTransactionManager getDataSourceTransactionManager() {
    return new DataSourceTransactionManager(getDataSource());
}

然后注释您想要事务性的服务方法：

@Transactional(transactionManager = "DataSourceTransactionManager", timeout = 60, rollbackFor = { Exception.class})
于 2020-01-08T22:37:12.817 回答