我正在编写一个简单的应用程序,它将与服务器连接。但是我也想发送简单的聊天命令(见Console.ReadLine
下文)。但是,此脚本无法访问, string Message = Console.ReadLine();
因为它在bytesRead = clientStream.Read(message, 0, 4096);
.
我想继续这个脚本,但是如果有字节传入,它应该处理它们(就像它现在正在做的那样),如果没有字节传入,它应该通过脚本并等待用户输入)。如何做到这一点?
TcpClient tcpClient = (TcpClient)client;
NetworkStream clientStream = tcpClient.GetStream();
byte[] message = new byte[4096];
int bytesRead;
while (true)
{
bytesRead = 0;
try
{
// Blocks until a client sends a message
bytesRead = clientStream.Read(message, 0, 4096);
}
catch (Exception)
{
// A socket error has occured
break;
}
if (bytesRead == 0)
{
// The client has disconnected from the server
break;
}
// Message has successfully been received
ASCIIEncoding encoder = new ASCIIEncoding();
// Output message
Console.WriteLine("To: " + tcpClient.Client.LocalEndPoint);
Console.WriteLine("From: " + tcpClient.Client.RemoteEndPoint);
Console.WriteLine(encoder.GetString(message, 0, bytesRead));
// Return message
string Message = Console.ReadLine();
if (Message != null)
{
byte[] buffer = encoder.GetBytes(Message);
clientStream.Write(buffer, 0, buffer.Length);
clientStream.Flush();
}