3

我有 2 张桌子，桌子 1 和桌子 2。

table1 有字段：

id
atype
adesc
aid

table2 有字段：

id
aid
adesc
value_1
value_2



$query1 = mysql_query("Select DISTINCT atype from table1");
while($row = mysql_fetch_array($query1)){
    $atype = $row['atype'];
    $query2 = mysql_query("Select adesc from table1 where atype='$atype' and aid IN (Select aid from table2 ) order by id asc");
    while($row2 = mysql_fetch_array($query2)){
        // i know query2 can only get adesc, so i need value_1 and value_2 in this
        echo $row2['adesc'] .'>> '. (this should be value1 from table2) .'>> '. (this should be value2 from table2);
    }
}


我也想得到value_1and value_2。任何帮助，将不胜感激。




编辑：
table1 值在我的数据库中（分别为 atype、aid、adesc）：

type1 111 'this is type 1'
type1 111 'this is type 1'
type2 112 'this is type 2'
type3 113 'this is type 3'
type4 114 'this is type 4'
type1 111 'this is type 1'
type4 114 'this is type 4'
type2 112 'this is type 2'

我的 table2 上的值（分别为aid、adesc、val1、val2）：

111  'this is type 1' 100 50
111  'this is type 1' 100 50
112  'this is type 2' 300 500
113  'this is type 3' 100 50
112  'this is type 2' 100 50
114  'this is type 4' 100 50
111  'this is type 1' 100 50

我真正想投影的是：

type1
      (sum)value_1 (sum)value_2
type2 
      (sum)value_1 (sum)value_2
type3
      (sum)value_1 (sum)value_2
type4
      (sum)value_1 (sum)value_2
4

3 回答 3

1 
    $query2 = mysql_query("Select t1.adesc, t2.value_1, t2.value_2 from table1 as t1, table2 as t2 where t1.atype='$atype' and t1.aid = t2.aid order by t1.id asc");

    while($row2 = mysql_fetch_array($query2)){
        // i know query2 can only get adesc, so i need value_1 and value_2 in this
        echo $row2['adesc'] .'>> '. $row2['value_1'] .'>> '. $row2['value_2'];
    }

更新：

$sql = <<<SQL
select t1.adesc, sum(t2.value_1) as v1, sum(t2.value_2)  as v2
from 
table1 as t1,
table2 as t2

where 
t1.aid = t2.aid 
group by t1.atype

order by t1.atype asc
SQL;
$query = mysql_query($sql);
while($row = mysql_fetch_array($query2)){
    // i know query2 can only get adesc, so i need value_1 and value_2 in this
        echo $row['adesc'] .'>> '. $row['v1']  .'>> '. $row['v2'];
}
于 2012-05-18T04:59:25.477 回答
0

在 SQL 中使用一个简单的内部连接，而不是您的两个选择：

select table1.adesc,atable2.value1 from table1,table2 where table2.adesc=table1.adesc and table1.aid=table2.aid order by table1.aid asc

编辑：

select table1.adesc,atable2.value1 from table1,table2 where table1.aid=table2.aid order by table1.aid asc
于 2012-05-18T04:59:24.637 回答
-1

此 SQL 查询应产生您想要的结果：

select adesc, 
       value_1, 
       value_2 

from   table1 

where  atype='$atype' and 
       aid IN (Select aid from table2 ) 

order by id asc
于 2012-05-18T04:57:48.027 回答