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我试着写一个日历。但是 for 循环只会打印出第一个月的天数。如果我尝试打印循环后的几天，它将起作用。有谁知道发生了什么？

cal_year = input('Enter a year (YYYY): ')

def not_common(year):
    if (year % 4 == 0):
        if (year % 100 == 0):
            if (year % 400 == 0):
                return 1
            else:
                return 0
        else:
            return 1
    else:
        return 0

leap = not_common(cal_year)

if leap == 0:
    print 'This is not a leap year'

elif leap == 1:
    print 'This is a leap year'

else:
    print 'unexpected calculation error'

y1900=1


day = ((cal_year-1900)*365)%7

month = ['Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec']
calendar = [range(1,32), range(1,29), range(1,32), range(1,31), range(1,32), range(1,31),\
         range(1,32),range(1,32),range(1,31),range(1,32),range(1,31),range(1,32)]

if (leap == 1):
    calendar[1] = range(1,30)

week = ['su','mo','tu','we','th','fr','sa']
r = 0
for i in range(0,12):
    print month[i]
    print ' '.join(str(y) for y in week)
    for j in range (1, (len(calendar[i])/7)+2):
        #cal =' '.join(str(x).zfill(2) for x in calendar[i][r*7:7*(r+1)])
            print ' '.join(str(x).zfill(2) for x in calendar[i][r*7:7*(r+1)])
            r += 1   
    print

print calendar[1]
print calendar[11]

故障线被认为是：' '.join(str(x).zfill(2) for x in calendar[i][r*7:7*(r+1)])

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1 回答 1

1

r每次开始新的一个月时，您都需要重新开始您的价值。

但是，您的代码还有其他问题，您假设每个月都从星期日开始，并且正好是 7 天的倍数。

于 2012-05-17T14:47:10.290 回答