我想在我的表中删除外键但进入此错误消息
mysql> alter table customers drop foreign key customerid;
ERROR 1025 (HY000): Error on rename of '.\products\customers' to '.\products\#sql2-7ec-a3' (errno: 152)
mysql>
我想在我的表中删除外键但进入此错误消息
mysql> alter table customers drop foreign key customerid;
ERROR 1025 (HY000): Error on rename of '.\products\customers' to '.\products\#sql2-7ec-a3' (errno: 152)
mysql>
The solution described here by Chris White worked for me.
The root problem is that MySQL creates both an index and a foreign key. Both must be removed (the foreign key first contrary to what Chris said).
show create table table_name;
SHOW CREATE TABLE `table_name`:
| table_name | CREATE TABLE `table_name` (
`id` int(20) unsigned NOT NULL auto_increment,
`key_column` smallint(5) unsigned default '1',
KEY `column_tablein_26440ee6` (`key_column`), <--- shows key name
CONSTRAINT `table_name_ibfk_1` FOREIGN KEY (`key_column`) REFERENCES <--- shows foreign key constraint name
`second_table` (`id`) ON DELETE SET NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8 |
Delete the foreign key constraint:
ALTER TABLE table_name DROP FOREIGN KEY `table_name_ibfk_1`;
Delete the key
ALTER TABLE table_name DROP KEY `column_tablein_26440ee6`;
That did it for me.
它看起来像 MySQL 的错误消息中的一个错误。( http://bugs.mysql.com/bug.php?id=10333 )
使用 SHOW CREATE TABLEtable_name
查看外键的实际名称。生成外键名称拼写错误的查询时,看起来可能是 mysql 查询浏览器问题。
为避免在尝试删除外键时出现此错误,请使用约束名称而不是外键的列名。
当我尝试
mysql> ALTER TABLE mytable DROP PRIMARY KEY;
我得到了错误
ERROR 1025 (HY000): Error on rename of '.\database\#sql-454_3' to '.\database\mytable' (errno: 150).
我使用以下方法解决了它:
mysql> ALTER TABLE mytable DROP PRIMARY KEY, ADD PRIMARY KEY (column1,column2,column3);
一些对您有帮助的链接。
link 2 [look for Posted by Alex Blume on November 7 2008 5:09pm & Posted by Hector Delgadillo on January 21 2011 4:57am]
为避免在尝试删除外键时出现此错误,请使用约束名称而不是外键的列名称
You should try with the foreign key name as Fahim Parkar suggested. Actually that does not work always either.
In my case I used the
FOREIGN KEY `fk`(`col1`) REFERENCES `table2`(`col1`)
code to add the fk by creation.
The problem with this code that it is not valid and should throw some kind of syntax error, but still it added a foreign key with a random name.
When I added the fk with the right syntax:
CONSTRAINT `fk` FOREIGN KEY (`col1`) REFERENCES `table2`(`col1`)
the following code dropped it properly:
ALTER TABLE `table1` DROP FOREIGN KEY `fk`
So this kind of error can happen too if you try to remove a foreign key with an invalid name. It is important to view the table properties with
SHOW CREATE TABLE `table1`
and check the foreign key names if you get this kind of errors.