sql - 如何选择最早的日期和与之对应的数据

Question

我有一个非常简单的问题让我很头疼。

CUSTNMBR   |  first_date |  SOPNUMBE
----------------------------------------
3344771005 |  2012-05-03 |  334471961748         
3344771005 |  2012-04-04 |  334476873726

在上表中，我想返回最早的日期custnumbr，sopnumbe所以它看起来像这样

3344771005 |  2012-04-04 |  334476873726

我用这个

Select a.CUSTNMBR, min(a.Tax_Date) as first_date, a.SOPNUMBE
from SOP30200 as a
where a.CUSTNMBR = '3344771005'
Group by a.CUSTNMBR, a.SOPNUMBE

但它会返回所有变量，如果我敲掉a.sopnumbein 组，它会出错。

Answer 1

试试这个：

Select top 1 a.CUSTNMBR, a.Tax_Date as first_date, a.SOPNUMBE 
from SOP30200 as a 
where a.CUSTNMBR = '3344771005' 
order by a.Tax_Date asc

Answer 2

尝试

Select TOP 1 a.CUSTNMBR, min(a.Tax_Date)as first_date, a.SOPNUMBE
from SOP30200 as a
where a.CUSTNMBR = '3344771005'
Group by a.CUSTNMBR, a.SOPNUMBE'
ORDER BY 2 ASC