java - 双打、逗号和点

Question

我正在制作一个从用户那里获取双值的 Android Java 程序。如果我在计算机上运行该程序，由于我计算机的语言环境 EN_UK，它运行良好。但是当我用 FI_FI 语言环境在我的手机上运行它时，它就不起作用了。我知道原因：在英国，人们使用点作为小数分隔符，但在芬兰，小数分隔符是逗号。

DecimalFormat df = new DecimalFormat("#.#");
Double returnValue = Double.valueOf(df.format(doubleNumber));

当我使用逗号时，它说java.lang.NumberFormatException: Invalid double: "1234,5".

我怎样才能让它与他们一起工作，逗号和点？

Answer 1

使用 DecimalFormat 的其他构造函数之一：

new DecimalFormat("#.#", new DecimalFormatSymbols(Locale.US))

然后尝试使用两个分隔符解析它。

Answer 2

usingDecimalFormatSymbols.getInstance() 将生成默认语言环境的正确符号，因此您可以在运行的任何平台上正确使用它。

DecimalFormat df = new DecimalFormat("#.#", DecimalFormatSymbols.getInstance());

Answer 3

这应该适用于 Java(Tested) 和 android :)

• 类名：In18Helper.java

  package com.akmeher.app.utils;
  
  import java.text.NumberFormat;
  import java.text.ParseException;
  import java.util.Locale;
  
  public class In18Helper {
      private final static In18Helper mHelper = new In18Helper();
  
      public static final In18Helper getInstance() {
          return mHelper;
      }
  
      public double getDouble(String sValue, Locale locale) {
          NumberFormat numberFormat = NumberFormat.getInstance(locale);
  
          Number parse = null;
          try {
              parse = numberFormat.parse(sValue);
          } catch (ParseException e) {
              e.printStackTrace();
          }
  
          return parse == null ? 0 : parse.doubleValue();
      }
  
  }
  

• 类名：Application.java

  package com.akmeher.app;
  
  import java.util.Locale;
  import com.akmeher.app.utils.In18Helper;
  
  public class Application {
  
      static DataModel[] testData = new DataModel[] {
              new DataModel("1.034567", Locale.ENGLISH),
              new DataModel("1,0345.67", Locale.ENGLISH),
              new DataModel("1.0345,67", Locale.GERMANY),
              new DataModel("1,034,567", Locale.CANADA),
              new DataModel("1.034567", Locale.KOREA),
              new DataModel("1,03.4567", Locale.ITALY) };
  
      /**
       * @param args
       */
      public static void main(String[] args) {
  
          for (int i = 0; i < testData.length; i++) {
                      double d = In18Helper.getInstance().getDouble(testData[i].mValue,
                      testData[i].mLocale);
  
              System.out.println("Trial Value: "+testData[i].mValue+" for Locale: "+testData[i].mLocale+" converted to: "+d);
          }
      }
  
      private static class DataModel {
          String mValue;
          Locale mLocale;
  
          public DataModel(String value, Locale locale) {
              this.mLocale = locale;
              this.mValue = value;
          }
      }
  }
  

输出：

Trial Value: 1.034567 for Locale: en converted to: 1.034567 Trial Value: 1,0345.67 for Locale: en converted to: 10345.67 Trial Value: 1.0345,67 for Locale: de_DE converted to: 10345.67 Trial Value: 1,034,567 for Locale: en_CA converted to: 1034567.0 Trial Value: 1.034567 for Locale: ko_KR converted to: 1.034567 Trial Value: 1,03.4567 for Locale: it_IT converted to: 1.03

希望这将有助于有人使用。

Answer 4

public static Double parseDoubleTL(String value){
    DecimalFormat df =  new DecimalFormat("#.#", new DecimalFormatSymbols(new Locale("tr_TR")));
    Double doublePrice = 0.0;
    try {
        doublePrice =  df.parse(value).doubleValue();
    } catch (ParseException e) {
        Log.w(MainActivity.TAG,"Couldnt parse TL. Error is "+e.toString());
    }
    return doublePrice;
}

Answer 5

不是最好的方法，但对我有用；

    Double val=null;
    try{
        val=Double.valueOf(value);
    }catch(Exception e){
        val=Double.valueOf(value.replace(',','.'));
    }
            Double val=null;
    try{
        val=Double.valueOf(value);
    }catch(Exception e){
        val=Double.valueOf(value.replace(',','.'));
    }
    return val;

Answer 6

我的错误：

java.lang.NumberFormatException: Invalid float: "1,683.88"

...这对我有用

replace(",", "")

Answer 7

DecimanFormat df = new DecimalFormat("#.#");