php - 从控制器任务 joomla 调用视图方法

Question

我正在尝试通过 MVC 创建 Joomla2.5 组件。我想从入口点的 task=jump 将控制器定向到 view.xml.php 中定义的 mydisplay() 方法。谢谢。

/ROOT/components/com_api/views/api/view.xml.php

<?php
defined('_JEXEC') or die('Restricted access');

// import Joomla view library
jimport('joomla.application.component.view');

/**
 * XML View class for the Api Component
 */
class ApiViewApi extends JView
{
// Overwriting JView display method

function mydisplay($tpl = null)
{
//echo JRequest::getVar('task');

    //$this->get('Ister');
    // Assign data to the view
    $this->msg = $this->get('xCredentials');

    // Check for errors.
    if (count($errors = $this->get('Errors')))
    {
        JError::raiseError(500, implode('<br />', $errors));
        return false;
    }

    // Display the view
    parent::display($tpl);
}



}
?>

ROOT/components/com_api/api.php（入口点控制器）

<?php
// No direct access to this file
defined('_JEXEC') or die('Restricted access');

// import joomla controller library
jimport('joomla.application.component.controller');

// Get an instance of the controller prefixed by Api
$controller = JController::getInstance('Api');


// Perform the Request task
$controller->execute(JRequest::getCmd('task'));

$controller->redirect();

?>

ROOT/components/com_api/controller.php（任务=跳转的控制器）

<?php

// No direct access to this file
defined('_JEXEC') or die('Restricted access');

// import Joomla controller library
jimport('joomla.application.component.controller');
/**
 * Api Component Controller
 */
class ApiController extends JController
{
function jump()
  {
    //parent::display();


/* invoke mydisplay method from view.xml.php, located in views*/

  }
}

执行 task=jump 后如何在 view.xml.php 中调用 mydisplay() 方法？

Answer 1

Try

$view = $this->getView('Api', 'xml');
$view->setModel($this->getModel('Api'), true);
$view->display();

Answer 2

您可以尝试将其放入控制器的跳转功能中

$view = $this->getView('API');
$view->mydisplay();