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如何使用方法作为参数InvokeMember?我是说

没有反思

ContainerEvents ems = new ContainerEvents();
Test ob1 = new Test(4);
Exam ob2 = new Exam(1);
FExam ob3 = new FExam(1);
Check ob4 = new Check(5);
ems.Setplus = new Super(ob1.Write);
ems.Setplus = new Super(ob2.Write);
ems.Setplus = new Super(ob3.Write);
ems.Setplus = new Super(ob4.Write);
ems.Run();

超级是代表。

通过反思,我想做同样的事情

Type type1 = typeof (Test);
Type type2 = typeof (Exam);
Type type3 = typeof (FExam);
Type type4 = typeof (Check);
Type events = typeof (ContainerEvents);
object eventer = Activator.CreateInstance(events);
events.InvokeMember("Setplus",BindingFlags.InvokeMethod,null,eventer,)

但我不知道要发送什么作为参数。创建Super对象实例?

Setplus 是一个属性

public Super Setplus
{
    set { obj.activate += value; }
}

obj - 类 Event 的对象

public class Event
{
    public event Super activate ;
    public void act()
    {
        if (activate != null) activate();
    }
}
4

1 回答 1

1

相当于:

ContainerEvents ems = new ContainerEvents();
Test ob1 = new Test(4);
ems.Setplus = new Super(ob1.Write);

这是:

object ems = Activator.CreateInstance(typeof(ContainerEvents));
object ob1 = Activator.CreateInstance(typeof(Test), new object[] { 4 });
object super = Delegate.CreateDelegate(typeof(Super), ob1, "Write");
ems.GetType().GetProperty("SetPlus").SetValue(ems, super, null);
于 2012-05-06T17:42:39.663 回答